What is Integration by parts: Definition and 437 Discussions

In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivative. It is frequently used to transform the antiderivative of a product of functions into an antiderivative for which a solution can be more easily found. The rule can be thought of as an integral version of the product rule of differentiation.
The integration by parts formula states:











a


b


u
(
x
)

v


(
x
)

d
x



=


[


u
(
x
)
v
(
x
)



]



a


b






a


b



u


(
x
)
v
(
x
)

d
x






=
u
(
b
)
v
(
b
)

u
(
a
)
v
(
a
)




a


b



u


(
x
)
v
(
x
)

d
x
.






{\displaystyle {\begin{aligned}\int _{a}^{b}u(x)v'(x)\,dx&={\Big [}u(x)v(x){\Big ]}_{a}^{b}-\int _{a}^{b}u'(x)v(x)\,dx\\[6pt]&=u(b)v(b)-u(a)v(a)-\int _{a}^{b}u'(x)v(x)\,dx.\end{aligned}}}
Or, letting



u
=
u
(
x
)


{\displaystyle u=u(x)}
and



d
u
=

u


(
x
)

d
x


{\displaystyle du=u'(x)\,dx}
while



v
=
v
(
x
)


{\displaystyle v=v(x)}
and



d
v
=

v


(
x
)
d
x


{\displaystyle dv=v'(x)dx}
, the formula can be written more compactly:





u

d
v

=

u
v


v

d
u
.


{\displaystyle \int u\,dv\ =\ uv-\int v\,du.}
Mathematician Brook Taylor discovered integration by parts, first publishing the idea in 1715. More general formulations of integration by parts exist for the Riemann–Stieltjes and Lebesgue–Stieltjes integrals. The discrete analogue for sequences is called summation by parts.

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  1. T

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  2. J

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  3. F

    Integration by Parts using Ln(x)

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  4. Fernando Revilla

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  5. A

    Integration by Parts with Complex Exponentials

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  6. T

    Problem with the expansion of integration by parts

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  7. trollcast

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  8. V

    Integral of 1/sqrt(x)exp(-ix) dx using integration by parts

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  9. 7

    Some weird integration by parts to derive momentum operator

    In a Griffith's book (page 15-16) an author derives a momentum operator. In the derivation he states that he used a integration by parts two times. He starts with this equation which i do understand how to get to. $$ \begin{split} \frac{d \langle x \rangle}{dt} = -\frac{i\hbar}{2m}...
  10. L

    Integration by parts involving square root

    Homework Statement |x3sqrt(4-x2)dx Homework Equations uv - | vdu The Attempt at a Solution u = x2 v = -1/3(4-x2)3/2 du = -2xdx dv = x(4-x2)1/2 uv - | vdu x2(1/3)(4-x2)3/2 - | 1/3(4-x2)3/2(2xdx) x2(1/3)(4-x2)3/2 +(1/3)|(4-x2)3/2(2xdx) u = 4 - x2 du = -2xdx...
  11. W

    Integrate by Parts: x^5 * sqrt(x^3 + 5)

    Homework Statement Integrate by parts.Homework Equations (integral) (x^5 * sqrt(x^3 + 5) dx)The Attempt at a Solution i've tried using simple substitution, not by parts. integral (x^3 * x^2 * sqrt(x^3 + 5) dx u=x^3 + 5 du=3x^2 1/3(integral) (u-5) * u^1/2 du 1/3(u^3/2 - 5u^1/2)...
  12. W

    The Integration by Parts Method: How to Integrate x * 5^x

    Homework Statement integrate by parts. Integral: x * 5^xHomework Equations The Attempt at a Solution i got to (1/ln5) * 5^x ;; and I'm not sure how to integrate further.
  13. N

    Integration by parts of derivative of expectation value problem

    Homework Statement I don't know how the writer of the book took integral of the first statement and got the second statement? Can anybody clarify on this? Homework Equations Given in the photoThe Attempt at a Solution When I took the integral I just ended up with the exact same statement but...
  14. MarkFL

    MHB Integration by Parts: Calculus Integral Help?

    Here is the question: Here is a link to the question: Calculus integral help? - Yahoo! Answers I have posted a link there to this topic so the OP can find my response.
  15. E

    Is Integration by Parts the Key to Solving Complex Equations?

    Hey guys, Need you push to proceed further with integration by parts: ∫e3x*3*x2*ydx=y∫e3x*3*x2dx setting u=3*x2-------du=6*x dx dv= e3*xdx--- v= 1/3* e3*x ∫ e3*x*3*x2*ydx=y*(3*x2* 1/3* e3*x-∫6*x*1/3* e3*xdx) =y*(3*x2* 1/3* e3*x-6/3*∫x*e3*xdx)...
  16. dwdoyle8854

    Integration by parts (problem plus question)

    Homework Statement I've run into this problem a few times, where I get the right answer, but multiplied by a constant where I would have it divided by the constant or vice versa. "First make a substitution and then use integration by parts to evaluate the integral" ∫cos(√x)dx...
  17. S

    Integration by Parts in 2D: How to Apply the Rule in Polar Coordinates?

    The integration by parts rule in two dimensions is \int_{Ω}\frac{\partial w}{\partial x_{i}} v dΩ = \int_{\Gamma} w v \vec{n} d\Gamma - \int_{Ω} w \frac{\partial v}{\partial x_{i}} dΩ I have two examples in polar coordinates In first example I have \vec{n}=\vec{n_{r}} \int_{\Gamma}...
  18. Mandelbroth

    Integration by Parts versus the Power Rule

    Recently, a friend of mine asked for help on their calculus homework. The problem was to find \int cos(ln \ x) \ dx. However, I've never gotten around to memorizing the derivatives and integrals of the trig functions. I know that you can do it using integration by parts, with \int cos(ln \...
  19. C

    MHB Integrate by Parts: Solving Difficult Integrand

    I am trying to integrate a difficult integrand. \[1/2*\int \sin(\sqrt(3)/2x)*\sec(\sqrt(3)x)\, dx\] I know that it requires to use integrate by parts. Which function do I use to for the differential and integrable?
  20. H

    Difficult indefinite integral (mix of integration by parts and/or substitution)

    Homework Statement I do not know how to solve the following indefinite integral. I personally think it is very difficult and would appreciate it had someone can explain it step by step? Homework Equations / The Attempt at a Solution This integral must been solved by mix of...
  21. A

    How can integration by parts be used twice to solve ∫ e^at. sinωt dt?

    ∫ e^at. sinωt dt This is the second part of an electrical circuit DE problem from our notes (first part not required to solve the above integral) however in-between this integral and the answer our professor only told us that we would get to the answer by using integration by parts twice. I am...
  22. DocZaius

    Integration by parts not working for a particualr integral

    Integration by parts not working for a particular integral When I attempt to use the method of integration by parts on the below integral, I don't get anywhere since I only arrive at the statement a = -b +b -a where a is the integral and b is the boundary term. \int e^{-x}\text{Cos}[k...
  23. B

    How Do You Solve the Integral of ln^2(6x) Using Integration by Parts?

    Hi all this is my first post hopefully i do it right. Homework Statement integrate ln^2(6x)dx The Attempt at a Solution *integral* ln^2(6x)dx u=ln^2(6x) dv=dx du=(2ln(6x))/x dx v=x xln^2(6x)-*integral*x(2ln(6x))/x dx xln^2(6x)-2*integral*ln(6x) dx u=ln(6x) dv=dx du=1/x...
  24. alane1994

    MHB Integration by Parts: Get v in udv=uv-vdu

    When integrating by parts the formula is \int{u} dv=uv-\int{v} du I understand where to get the u, and du... but where does one get the v?
  25. A

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    Homework Statement ∫x3e5x2 dx Homework Equations uv-∫vdv The Attempt at a Solution I've tried this one a few times, but keep getting answers that are just out there. Could someone, if possible, work out just the beginning.
  26. T

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    Homework Statement Consider the following integral: I=\int^{\pi/4}_{0}cos(xt^{2})tan^{2}(t)dt I'm trying to compute as many terms as possible of its asymptotic expansion as x\rightarrow\infty. Homework Equations x The Attempt at a Solution Let u=cos(xt^{2}). And...
  27. E

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    I was wondering if someone can show me or point me to a worked out example using integration by parts for more than one variable (as used in relation to pde's, for example). While I took pdes and calc 3, its been awhile and I don't know if I ever understood how to work out a concrete example...
  28. R

    What is the difference b/w cos(lnx) and cosxlnx? integration by parts

    Ok I have to integrate -->∫cos(lnx) dx. could I use cos =U, -sinx=du, dv=lnxdx, v = 1/x I know the difference technically, but in this situation it is kinda weird. because the formula f(x)g(x)= uv-∫vdu. I thinking if they were number like 9(3) it would equal 27 so f(g) = f times G? but then...
  29. L

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  30. N

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    Homework Statement αh=α-ε+ih ΔαH/Δα= dαH/dα = d/dα x (α-ε+ih) = 1-(dε/dα)
  31. S

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    Homework Statement Evaluate the following indefinite integral: ∫(sin(ln16x))/xdx Homework Equations The Attempt at a Solution let u = ln16x therefore du=16/16x=1/x ∫sinudu =-cosu =-cos(ln16x) Why is this showing as the wrong answer?
  32. I

    Wave packet - Integration by parts

    Homework Statement Hi , I am reading a little on introductory QM , initial chapters on waves. They have given an integral for a wavepacket , assuming at t= 0. Which is: ψ(x,0) = \int A cosk'x dk' (I don't know how to define limits to the integral in Latex upper = k+Δk , lower limit =...
  33. N

    Integration by Parts: Solving ∫(1/x^2*ln(x))

    Homework Statement ∫\frac{1}{x^{2}*ln(x)} Homework Equations ∫udv = uv-∫vdu u=ln(x) du = \frac{1}{x}dx dv = x^{2}dx v = \frac{x^{3}}{3} The Attempt at a Solution Using the above formula I got \frac{x^{3}}{3}*ln(x) - \frac{x^{3}}{9} + C Am I doing this correctly or do I...
  34. B

    Integration by Parts: Understanding dv & dx

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  35. J

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  36. P

    Intuition behind Integration by parts

    I have some problems understanding the intuition behind the integration by parts technique. I don't quite see why you solve for \int u(x)v\prime (x), instead of one of the other parts, what makes it easier to solve for that particular term? And in general when working with integration...
  37. S

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    Hello. I'm just trying to understanding something here. I was taught integration by parts by my professor in what looks to be like an untraditional way. From my understanding, the theorem states: ∫udv = uv - ∫vdu We were given an example in class of: ∫exsin(x)dx =∫ex∫sin(x)dx -...
  38. B

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  39. B

    Integration by Parts in Calculus: Understanding the Process and Its Applications

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  40. S

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  41. L

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  42. L

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  43. B

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  44. R

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  45. R

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  46. O

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  47. I

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  48. S

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  49. idir93

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  50. Roodles01

    Integrate 1/x(2/3) - Solve for 3 Cube Root 3

    knowing the standard form for integration by parts is ∫ f(x)g'(x) dx = f(x)g(x) - ∫f'(x)g(x) dx I have what is an innocuous looking part of an equation which I can't solve. the f(x) part in this case is; ln(5x) which is easy enough i.e. 1/x the second part 1/(x(2/3)) is the bit I...
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