The Nikon DX format is an alternative name used by Nikon corporation for APS-C image sensor format being approximately 24x16 mm. Its dimensions are about 2⁄3 (29 mm vs 43 mm diagonal, approx.) those of the 35mm format. The format was created by Nikon for its digital SLR cameras, many of which are equipped with DX-sized sensors. DX format is very similar in size to sensors from Pentax, Sony and other camera manufacturers. All are referred to as APS-C, including the Canon cameras with a slightly smaller sensor.
Nikon has produced 23 lenses for the DX format, from macro to telephoto lenses. 35mm format lenses can also be used with DX format cameras, with additional advantages: less vignetting, less distortion and often better border sharpness. Disadvantages of 35mm lenses include generally higher weight and incompatible features such as autofocus with some lower-end DX cameras. Nikon has also produced digital SLRs that feature the larger Nikon FX format sensor that is the size of the 135 film format.
In 2013, Nikon introduced a high-end compact camera with a DX-sized sensor, the Nikon Coolpix A, featuring an 18.5 mm lens.
Say the limit of the integral is from 0 to t and the integral is ended with a dt. Is this okay?
Generally, all the integrals I see with a variable limit end with a d-letter that is not the same as the variable in the limit. ie: limit is from 0 to t, ends with du
I'm having a tough time rewriting integrals from one form to another when the first integrand is not a function of two variables.
As an example, when writing the integral to find the volume of a tetrahedron, I can easily write all 6 versions of the integral based on z = 1 - x - y or some...
Is this integral doable at all ?
x^4 dx / (x^2+a^2)^(3/2)
I have tried several u-substitutions but none of them seem to make the form of the integral any simpler
Homework Statement
\int x/(2x+1) dx
Homework Equations
The Attempt at a Solution
I tried factoring out the 2 on the bottom to get 1/2 \int x/(x+1/2). then I put 1/2 \int x+(1/2)-(1/2)/(x+1/2) dx.
from that i had, 1/2 \intdx - 1/2\intdx/(x+1/2)
finally x/2 - 1/4 ln...
I'm having serious trouble with the concept of u-substitution. Using this as an example
int 2x(x2−1)4
I make u = x2−1
first thing I don't get is why du/dx = 2x is rearranged to du = 2xdx. Second thing I don't get is where the dx dissappears to. In this method is 2xdx just being represented as...
Justification of ψ*ψdx as probability density of particle between x and x+dx using light's E-field and diffraction by slit.
This isn't a homework problem, rather it was on the list of things to know for the exam. They don't really go over it in Griffiths Quantum Mechanics books. So are any...
Every book that I have checked, it says the dx after the integrand is just there to remind us that it is the variable x that is being integrated. I however am trying to see some other meaning. There must be some reason why, when we integrate 2x, it is also multiplied by dx. I have tried real...
How do you solve these 3 integrals? :
Integral 1 : 1/(1+sqrt(x)) dx
Integral 2: (x^3)*(e^x^2)
Integral 3: (x*e^x)/((x+1)^2)
I have no idea how to solve these integrals..
Integral: sqrt(4-x^2)*sign(x-1) dx
Can someone help me with this integral?
I've never worked with a sign funtion before, so I have absolutely no idea how to solve this integral
Homework Statement
Find the integral
f(x) = x^3 sqrt(x^2 + x^8 + 8) cox(x) dx
The Attempt at a Solution
I need help starting. It appears to be either integration by parts and/or substituion.
integral (x^2 - 2x) e^-x dx
Im just wondering if there's a fast way to calculate this integral or is the only way to do it by parts twice. The prof didnt show any work in the solution and went right to the solution. Am I missing something obvious?
I'm supposed to be Integrating 1/(4+x^2)^2 dx using trigonometric substitutions, but I do not know how to get started with this one.
Am I supposed to rewrite this as 1/sqrt((4+x^2)^2) and then use the reference triangle? I've tried expanding the bottom, but that doesn't get me anywhere...
1. Homework Statement
This is part of a find the electric field problem. I've narrowed down the part I find confusing.
Consider a right triangle, with legs of length x and R. Angle θ is opposite x. Leg x is a segment of a ray starting where lines x and R intersect. There is a differential...
Homework Statement
This is part of a find the electric field problem. I've narrowed down the part I find confusing.
Consider a right triangle, with legs of length x and R. Angle θ is opposite x. Leg x is a segment of a ray starting where lines x and R intersect. There is a differential length...
Homework Statement
Hi I am working on a solution for the integral the integral
\int_{-\infty}^{\infty} (\frac{sin(x)}{x})^2 dx
Homework Equations
The Attempt at a Solution
I know from theory that
\int_{-\infty}^{\infty} f(x) dx = \int_{-\infty}^{a} f(x) dx +...
Does "dx" does not make change in front of the integral?
Hello I got one question. I am confused by seeing dx in front of the integral.
For ex.
\int f(x) dx = F(x) + C
where
F'\!(x) =\frac {d}{dx} F(x) = f(x).
As we know F'(x)=f(x), then why F'(x) = f(x) . dx
Isn't supposed...
Hi everyone,
Can you tell me how to integrate the following equation?
\int\frac{1}{x^2 + 1} \ dx
I've tried the substitution method, u = x^2 + 1, du/dx = 2x. But the x variable is still exist.
Also, the trigonometry substitution method, but the denominator is not in \sqrt{x^2 + 1}...
Given the double integral \int\int_R \sqrt{}x^2+y^2 dx dy where R is the unit circle.
We are only given the equation for the unit circle but don't we need more equations so I can change the equations to a single variable and then find the Jacobian so how do I find the Jacobian.
How do I find a...
When solving an ODE, physicsts sometimes multiply the differential dx.
Example
df/dx = x/2
df = (x/2)dx
f = x^2 + c
I've always been told that this mathematically unsound, but I've never been told why. Is it because the necessary constant c may not necessarily be additive? Are...
Homework Statement
\frac{dx}{(4+x^2)^2}Homework Equations
I understand that \frac{dx}{a^2+u^2} = \frac{1}{a} tan -1 \frac{u}{a} + cThe Attempt at a Solution
The extra square is throwing me off for some reason. If I let a=2 and u=x it doesn't seem to help because of the whole term being...
Homework Statement
integrate: e(x^2 +x)(2x+1) dx
The Attempt at a Solution
let u= e(x^2 +x)
du=e(x^2 +x)(2x+1)dx
integral e(x^2 +x)(2x+1) dx = integral 1/u du
am I on the right track? i didnt get the same answer as the prof...
Homework Statement
y' = y(siny) + x does this have a unique solution ,
with the intial value of f(0)= -1
The Attempt at a Solution
the partial dervative with respect to y is
del(x)/del(y) = siny + cosy(y) this is continuous on the rectangle including
(0 , -1 ) so...
Because of circumstance (my desire to graduate in 5 years or less), I've been forced to attempt Calc 2 in 2 months time online over the summer. About 75% of it is going smoothly (compared with 105% or so of Calc 1).
Homework Statement
I'm to solve the indefinite integral: \int x *...
Hi all
Can you solve the following integration: -
Integration [ cos(x)/(c+cos(x)) ] by dx
where c is a constant
or that one: -
Integration [ 1/(c+cos(x)) ] by dx
if one is solved I will be able to make the other
Hello all,
I am trying to solve a line integral:
Find the value of \int -2y dx + x^2 dy over the circle x^2 + y^2 = 9
as you can see, this is a line integral, and I am trying to figure a quick way how it should be solved.
I thought of converting coordinates to (sint,cost) which will...
This isn't really a homework question, but it has been bugging me for ages.
In \int f(x) \, dx what exactly does the 'dx' represent? Is it a differential? What is a differential?
I only use the 'dx' part to identify the variable that the function is being integrated with respect to... or...
What is the integral of ∫ e^ (x^2 +sinx) dx
I got the answer e^(x^2+sinx)/(2x+cosx) but I know that is wrong. I don't understand how you treat the + part for an e^() problem.
Hey guys. I've started studying Physics at home, but only the theory side with a little mathematics. So i would like to try, if i can, to introduce a little calculus to my work. But the problem is i find calculus a mind boggle, i understand All the GCSE math that i did. Could someone explain to...
Homework Statement
Integrate the following:
(Ill use { as the integration sign)
{x5(lnx)2 dx
Homework Equations
{u dv = uv - {v du
I'm really new to integration by parts, and unfortunately I am having to learn it out of a book for now. I sort of get the idea, but this one just doesn't look...
I am in the middle of a problem and I have to take the integral of "dx" This is very confusing, I would guess x or 1 but neither really makes sense to me. How would you take the derivative of something to form dx?, similarly how would you take the derivative of dx^2.
Aside from knowing that...
Homework Statement
What is the integral of sqrt(x^2-1)/x dx?
Homework Equations
The Attempt at a Solution
∫ √(x^2 - 1) dx / x
let x = sec u: u = sec^-1(x) and tan u = √(x^2 - 1)
dx = sec u tan u du
now the integral becomes
∫ √sec^2(u) - 1) sec u tan u du / sec u
=...
Homework Statement
Integrate: x^2 dx / (1-x)^1/2
Homework Equations
U substitution
The Attempt at a Solution
First I defined u = (1-x)^1/2
du = -dx/2(1-x)^1/2
dx = -2(1-x)^1/2 du
then for x
u^2 = 1-x
x = 1-u^2
integral of: (1-u^2)^2/u
= (u^4-2u^2+1) / u
= u^3-2u+1/u
integrating...
I was absent last friday when we went through it in class, so I'm completely lost when it comes to solving it. If anyone could explain how to do them I'd be extremely greatful. Thanks.
Homework Statement
It said use the substitution x = a sin theta.
Homework Equations
I'm not sure...
Homework Statement
By multiplying the integrand sec x dx by \frac{tan x + sec x}{tan x + sec x} find the integral of sec x dx
Homework Equations
d/dx sec x = tan x.sec x
d/dx tan x = sec^2 x
The Attempt at a Solution
sec x dx(\frac{tan x + sec x}{tan x + sec x}) =>
\frac{tan...
Homework Statement
Use Stokes Theorem to compute
\int_{L}^{} y dx + z dy + x dx
where L is the circle x2 + y2 + z2 = a2, x + y + z = 0
The Attempt at a Solution
I feel like this problem shouldn't be that hard but I can't get the right answer: (pi)a2/3.
I calculated the curl of F as...
I am reviewing differential equations, going through H.S. Bear's book Diff Eq: Concise Course.
The problem set for the variables separate section were pretty easy and straightforward except for this one, which I can't see how to arrive at the answer given in the book. I'm probably just missing...
I ran into an integral while working on response of a signal processing filter, it looks like:
\int_{-\infty}^{\infty} x^{2} e^{-x^{2}} dx
While trying integration by parts u = x^{2} we get du = 2xdx but can't proceed with dv = e^{-x^{2}} because then
v = \int e^{-x^{2}}
can't be...
Hi I have been thinking about an idea I have involving calculus that I think someone here can help me with. Is there a way you can determine a simple function (like f(x)=Ax) that has the same area dA from X to dX as another complicated function like f(x)=x^2. If you refer to the two...
I'm having trouble with this integral:
integral of 5sin^(3/2)x*cosx dx
any suggestions? i tried integration by substitution but it didnt work.
do i need to do integration by part?? help!
[SOLVED] Integrate (1/(1-cos x)) dx
Homework Statement
\int \frac{1}{1-cos x} dx
Homework Equations
The Attempt at a Solution
I found in the book where they used the cos x= \frac{1-z^2}{1+z^2}, but we haven't went over this in class yet. I'm wandering what my other options are...
If you are told to evaluate the integral and are given this problem:
∫ (e√x / √x) dx
This reads that the integral of (e) to the power of square root of x divided by the square root of x multiplied by the derivative of x is……
I have tried solving it and came up with this, is this...
Hi Ho!
If y=\sin x, \frac{dy}{dx}=\frac{d(\sin x)}{dx}=\cos x.
If x=\sin y, y=\arcsin x, and therefore \frac{dy}{dx}=\frac{d(\arcsin x)}{dx}=\frac{1}{\sqrt{1-x^2}}.
But, if x=\sin y, can \frac{dy}{dx} be done as \frac{dy}{dx}=\frac{dy}{d(\sin y)}=\frac{1}{\frac{d(\sin...