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Integral- Without using integration technnique

Chipset3600

Member
Feb 14, 2012
79
Hello MHB, how can i solve this without use integration technniques...

[TEX]\int tan(t)sec^3(t)dt[/TEX]
 

SuperSonic4

Well-known member
MHB Math Helper
Mar 1, 2012
249
Re: Integral- Without use integration technnique

Hello MHB, how can i solve this without use integration technniques...

[TEX]\int tan(t)sec^3(t)dt[/TEX]
How do you mean "without using integration techniques"? Surely you need integration techniques to solve an integral? Also what have you tried?

Hint: Let $u = \sec(t) = \frac{1}{\cos(t)}$
 

Chipset3600

Member
Feb 14, 2012
79
Re: Integral- Without use integration technnique

How do you mean "without using integration techniques"? Surely you need integration techniques to solve an integral? Also what have you tried?

Hint: Let $u = \sec(t) = \frac{1}{\cos(t)}$
I mean without: substitution, integration by parts...
 

Fantini

"Read Euler, read Euler." - Laplace
MHB Math Helper
Feb 29, 2012
342
Re: Integral- Without use integration technnique

I'm not sure that is possible, this is not an elementary integral (in the sense that it is the derivative of an elementary function, such as $\cos x$, $\sin x$, $\tan x$ and so on).
 

soroban

Well-known member
Feb 2, 2012
409
Re: Integral- Without use integration technnique

Hello, Chipset3600!

How can i solve this without use integration technniques?

. . [TEX]\int \tan\theta \sec^3\!\theta\,d\theta[/TEX]

Well, maybe you can see all this?


If we have: .[tex]f(x) \:=\:\tfrac{1}{3}\sec^3\!\theta + C[/tex]

Then: .[tex]f'(x) \:=\:\tfrac{1}{3}\cdot 3\sec^2\!\theta\cdot\sec\theta\tan\theta + 0 \;=\;\tan\theta\sec^3\!\theta [/tex]
 

Chipset3600

Member
Feb 14, 2012
79
Re: Integral- Without use integration technnique

Hello, Chipset3600!


Well, maybe you can see all this?


If we have: .[tex]f(x) \:=\:\tfrac{1}{3}\sec^3\!\theta + C[/tex]

Then: .[tex]f'(x) \:=\:\tfrac{1}{3}\cdot 3\sec^2\!\theta\cdot\sec\theta\tan\theta + 0 \;=\;\tan\theta\sec^3\!\theta [/tex]
[TEX]\int tan(t).sec^3(t)dt = \int sec^2(t).sec(t).tan(t)dt[/TEX]


Using the power rule now:


[TEX]\frac{sec^3(t)}{3}+C[/TEX]
 

Fantini

"Read Euler, read Euler." - Laplace
MHB Math Helper
Feb 29, 2012
342
Re: Integral- Without use integration technnique

You don't have a polynomial to apply the power rule, at least not until you use substitution.