Finding the maximum height given multiple variables

In summary, an object thrown with a speed of 1.99 times the initial velocity from the surface of Saturn's moon Iapetus will reach a maximum height of 29.30 times the maximum height reached when thrown from the surface of Mercury. This is calculated using the equation Vf2-Vi2 = 2a∆y, with the acceleration due to gravity on Iapetus being 0.223 m/s2 and on Mercury being 3.70 m/s2.
  • #1
kaitwhit
1
0

Homework Statement



A 4.27-kg object is thrown vertically upward from the surface of Mercury, where the acceleration due to gravity is g1 = 3.70 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.99v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.


Homework Equations


Vf2- Vi2 = 2a∆y


The Attempt at a Solution


y2=29.30 y1
 
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  • #2
kaitwhit said:

Homework Statement



A 4.27-kg object is thrown vertically upward from the surface of Mercury, where the acceleration due to gravity is g1 = 3.70 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.99v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.


Homework Equations


Vf2- Vi2 = 2a∆y


The Attempt at a Solution


y2=29.30 y1
Hi kaitwhit, Welcome to Physics Forums.

Try using the x2 and x2 buttons on the edit panel header to create superscripts and subscripts in your equations :wink:

Can you show the work you did to arrive at your result so that we can know how to help?
 

Related to Finding the maximum height given multiple variables

1. How do you calculate the maximum height given multiple variables?

To calculate the maximum height, you will need to use the equation: h = (v^2 * sin^2θ) / 2g where h is the maximum height, v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity.

2. What variables are needed to find the maximum height?

The variables needed to find the maximum height are the initial velocity, angle of projection, and acceleration due to gravity.

3. Can the maximum height be found using only one variable?

No, the maximum height cannot be found using only one variable. It is a combination of the initial velocity, angle of projection, and acceleration due to gravity.

4. What is the significance of finding the maximum height in a projectile motion problem?

Finding the maximum height is important in projectile motion problems because it helps determine the range, or horizontal distance, of the projectile. It can also be used to compare the heights of different projectiles or to determine the angle of projection for maximum height.

5. How does changing the initial velocity or angle of projection affect the maximum height?

Changing the initial velocity will directly affect the maximum height, as a higher initial velocity will result in a higher maximum height. The angle of projection also affects the maximum height, as a smaller angle will result in a lower maximum height. However, changing both variables simultaneously can have a complex effect on the maximum height.

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