- #1
Matthew117
- 2
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Hello everyone. So I have this one question which I thought was going to be pretty easy, but now I struggle with it. It says:
1. The question
A rock is thrown vertically up in the air with an initial velocity of 0.75ms-1. What would the rock's maximum theoretical height be?
I am currently in high school and usually there would be one more variable given to make solving easier. We also assume that there's no air resistance, just to make the calculations easier on our level.
The equations I think are relevant to this problem are:
KE = 1/2mv2
GPE = mgh
3. The Attempt at a Solution
In order to solve this I decided to set the two equations equal to each other. The final KE is going to be equal to GPE if we assume that all energy is transferred (please correct me on that one if I'm wrong).
Assuming that acceleration due to gravity = 10ms-1
(0.75)2m = 10mh
(9/32)m = 10mh
9/32 = 10h
h = 0.02813m
h = 2.81cm
This height looks very little to me, and I'm 100% sure it's wrong. My teacher wrote that question himself, so maybe he forgot to add one of the variables (it's not the first time something like this happened).
My test is this upcoming Wednesday and this really stresses me out as I feel like the answer is obvious but I can't find it...
Any input would be appreciated! Thanks :)
1. The question
A rock is thrown vertically up in the air with an initial velocity of 0.75ms-1. What would the rock's maximum theoretical height be?
I am currently in high school and usually there would be one more variable given to make solving easier. We also assume that there's no air resistance, just to make the calculations easier on our level.
Homework Equations
The equations I think are relevant to this problem are:
KE = 1/2mv2
GPE = mgh
3. The Attempt at a Solution
In order to solve this I decided to set the two equations equal to each other. The final KE is going to be equal to GPE if we assume that all energy is transferred (please correct me on that one if I'm wrong).
Assuming that acceleration due to gravity = 10ms-1
(0.75)2m = 10mh
(9/32)m = 10mh
9/32 = 10h
h = 0.02813m
h = 2.81cm
This height looks very little to me, and I'm 100% sure it's wrong. My teacher wrote that question himself, so maybe he forgot to add one of the variables (it's not the first time something like this happened).
My test is this upcoming Wednesday and this really stresses me out as I feel like the answer is obvious but I can't find it...
Any input would be appreciated! Thanks :)