What is the physical interpretation of f(0) in the optical theorem?

In summary, the optical theorem is a law of wave scattering theory that relates the forward scattering amplitude to the total cross section of the scatterer. It is derived from conservation of energy and probability and is widely applicable. The term "f(0)" refers to the scattering amplitude at an angle of zero, which is the amplitude of a wave scattered to the center of a distant screen. This implies a situation where the impact parameter is undefined and the incoming particles are spread out in space. The optical theorem also has consequences for situations involving localized wave packets, but this is not discussed in the Wikipedia article.
  • #1
erwinscat
7
0
Hello everyone. I have an understanding problem with the Optical theorem definition.

From Wikipedia :

"In physics, the optical theorem is a general law of wave scattering theory, which relates the forward scattering amplitude to the total cross section of the scatterer. It is usually written in the form:

[tex]\sigma _{tot}=\frac{4\pi}{k}Im f(0)[/tex]

where f(0) is the scattering amplitude with an angle of zero, that is, the amplitude of the wave scattered to the center of a distant screen. Because the optical theorem is derived using only conservation of energy, or in quantum mechanics from conservation of probability, the optical theorem is widely applicable and, in quantum mechanics, σtot includes both elastic and inelastic scattering. "

What does "f(0) is the scattering amplitude with an angle of zero, that is, the amplitude of the wave scattered to the center of a distant screen" exactly mean ? Are we talking about a head to head scattering ? Does angle zero mean there is no impact parameter ?

I do not understand the physical situation...any help is welcome !

Thanks a lot in advance,
Erwin
 
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  • #2
As far as I know, the impact parameter is undefined in this situation. The incoming particles are momentum eigenstates to a good approximation, and therefore spread out in space. It doesn't make sense to talk about an impact parameter unless you are considering the collision of localized wave packets that are significantly separated. The optical theorem may have consequences for that situation also, but I don't know anything about that.

Torquil
 
  • #3
Zero angle means there is no scattering ! The physical situation is as follow : a plane wave is sent on a fixed object called the "scatterer" on the wikipedia page (in section Derivation). Conservation of probability means that we have a relation between the total probability for any scattering at non zero angle (given by [itex]\sigma_\text{tot}[/itex]) and the non-scattered wave. f(0) gives the non-scattered wave which must interfere destructively with the incident wave for scattering to occur.
 

Related to What is the physical interpretation of f(0) in the optical theorem?

What is the optical theorem definition?

The optical theorem is a fundamental principle in optics that relates the scattering of light by a particle to its absorptive properties. It states that the total scattering cross section of a particle is equal to four times the imaginary part of its forward scattering amplitude.

What is the importance of the optical theorem in optics?

The optical theorem is important in optics because it allows for the calculation of the total scattering cross section of a particle without measuring the scattered light in all directions. This is useful in many applications, such as determining the size and shape of particles in a sample.

How is the optical theorem derived?

The optical theorem can be derived from the conservation of energy and momentum in the scattering process. It can also be derived from the Huygens-Fresnel principle, which states that each point on a wavefront acts as a source of spherical waves.

What are some real-world applications of the optical theorem?

The optical theorem has many practical applications, including the characterization of particles in aerosols, colloidal suspensions, and biological samples. It is also used in the design of optical devices, such as lenses and mirrors, and in the study of atmospheric phenomena, such as rainbows and halos.

Are there any limitations to the optical theorem?

Although the optical theorem is a useful tool in optics, it does have some limitations. It assumes that the particles being studied are spherical and that the incident light is monochromatic and linearly polarized. In reality, particles can have complex shapes and light can have a range of wavelengths and polarizations, which can affect the accuracy of the calculations.

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