- #1
zxcv784
- 4
- 0
Hi,
I am trying to integrate (x^5)/7680 . exp (-x/2) dx between 0 and 1. I've had various attempts at this and this is what i have done so far...
Taken the 1/7680 outside the integration
Using integation by parts I have assigned u=x^5 and dv/dx = exp(-x/2). when i integrate exp(-x/2) i get v = -2exp(-x/2), and du/dx = 5x^4 - is this correct?
This integration results in...
-2x^5exp(-x/2) - the integral of -8x^4 . exp(-x/2)
which also has a product so i do a series of integration of parts to nock down the power each time to get the solution in terms of a x^5 + x^4 +x^3 etc...
But i mut be doing something wrong as the answer is 1.4x10^-5 and i get 0.189!
I would really appreciate some help on this integration as I've spent so long trying to figure it out and this is my last resort!
Thanks
zxcv784
I am trying to integrate (x^5)/7680 . exp (-x/2) dx between 0 and 1. I've had various attempts at this and this is what i have done so far...
Taken the 1/7680 outside the integration
Using integation by parts I have assigned u=x^5 and dv/dx = exp(-x/2). when i integrate exp(-x/2) i get v = -2exp(-x/2), and du/dx = 5x^4 - is this correct?
This integration results in...
-2x^5exp(-x/2) - the integral of -8x^4 . exp(-x/2)
which also has a product so i do a series of integration of parts to nock down the power each time to get the solution in terms of a x^5 + x^4 +x^3 etc...
But i mut be doing something wrong as the answer is 1.4x10^-5 and i get 0.189!
I would really appreciate some help on this integration as I've spent so long trying to figure it out and this is my last resort!
Thanks
zxcv784