- #1
jason177
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Homework Statement
Find the volume of the solid that results when the region bounded by the curves y=16-x[tex]^{2}[/tex] and y=16-4x is revolved around x=8.
If you could show me how to do it with both the shell method and washer method it would be greatly appreciated.
Homework Equations
The Attempt at a Solution
When trying the shell method i tried to shift the graph to the left 8 units and then revolving it about the y-axis and got:
y=16-(x+8)[tex]^{2}[/tex] and y = 16-4(x+8) which gave me
2[tex]\pi[/tex]*[tex]\int^{-4}_{-8}[/tex]x(16-(x+8)[tex]^{2}[/tex] - (16-4(x+8))) dx
and that gave me a negative answer so I know that can't be right