Unifom accelaration question about racing

In summary, Go-Cart A travels at a constant speed of 20.0m/s. Go cart B accelerates uniformly from rest at a rate of 0.333m/s2, but eventually loses the race by a significant amount.
  • #1
captdestiny
5
0

Homework Statement


Two go-carts, A and B, race each other around a 1.0km track. Go cart A travels at a constant speed at 20.0m/s . Go cart B accelerates uniformly from rest at a rate of 0.333m/s2. Which go-cart wins the race ? and by how much ?

EDIT: When it says around it means they raced one lap around the track going at a constant speed, except for Cart B, its going at a constant acceleration

Don't go too deep into the shape of the track, it doesn't really matter, however if you still do, its going in a straight path.

Homework Equations


I don't know which to use.

The Attempt at a Solution



Well I know that Go-Cart A take 50 seconds to cross the line.

20m/s / 1000m = 50 seconds
 
Last edited:
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  • #2
Do you mean to say that the track is not circular? After all, you said that
race each other around
, by "around", did you mean perhaps that the segment is round?
If not, recall that kinematics equations:
[itex]
\large
x = \frac{at^2}{2}
[/itex]
Where a is your constant acceleration; But do clarify your stance on the shape of field etc...
Daniel
 
  • #3
Fixed
 
  • #4
Okay, thank's for allaying the mix-up.
What's stopping you from using the equation above? Find the time it took each to cross said distance, which will indicate firstly, who won... Then, measure how deficient/far was the loser by that moment in time.
Daniel
 
  • #5
Don't know what equation to use ...

so lost.. physics teacher was away for a week and the whole class is lost
 
  • #6
Okay, okay, not to worry, there's no need to panic.
You have, from my post:
[itex]
\large
x = \frac{at^2}{2}
[/itex]
So plug in your data here for each car.
In one, x is simply v*t(the one with the constant velocity).
in the other, the above mentioned formula.
Find T for each(a is the constant acceleration).
Compare the results; Whosever t is greater, lost the race(took him longer to cross the track).
Then, find where was the loser at the time T of the victor.
It's as simple as that,
But it would help greatly if you could point-out where you're having difficulties,
Daniel
 
  • #7
Thanks a lot Daniel, you're a life saver

MAY GOD BLESS YOUR WARM KIND HEART ! <33333333333333333
 
  • #8
So I reckon you solved it properly, well done! :)
Good job,
And keep up the good work,
Daniel
 

Related to Unifom accelaration question about racing

1. What is uniform acceleration in the context of racing?

Uniform acceleration refers to the constant change in velocity of an object moving in a straight line. In racing, this can be seen when a car maintains a constant increase in speed over a set distance.

2. How is uniform acceleration calculated in racing?

To calculate uniform acceleration in racing, the change in velocity is divided by the time it took to make that change. This can be represented by the formula a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

3. What are some examples of uniform acceleration in racing?

Some examples of uniform acceleration in racing include a car accelerating from 0 to 60 mph in a set amount of time, a runner increasing their speed consistently over a race, or a bike gaining speed down a straight track.

4. How does uniform acceleration affect a race?

Uniform acceleration can greatly impact a race, as it determines how quickly an object can change its velocity. In racing, having a higher acceleration can give a competitor an advantage in reaching the finish line first.

5. What factors can impact uniform acceleration in racing?

Several factors can affect uniform acceleration in racing, including the weight and power of the vehicle, the condition of the track or road surface, and external forces such as wind or friction. Additionally, the skill and technique of the driver or athlete can also play a role in achieving uniform acceleration.

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