- #1
Aldebo
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∂hi all. I sort of understand this question but not fully so here it goes:
A shaft carrying a flywheel of diameter 565mm and mass 210 kg is required to run at a speed of 710 rev/min. If the working speed is to be reached in 16 seconds from rest and the coefficient of friction between shaft and bearing is 0.3, determine,
The torque required to overcome inertia and friction .
so far I've worked out T=IA (Torque = Inertia x Angular acceleration), however where is the coefficient of 0.3 involved and how.
any help will be much appreciated Relevant equations
T=Ia ∴ I=(mr²)/2
w2=w1+at ∴ a=(w2-w1)/t
However I'm not sure where the coefficient of friction is involved in all this, maybe a separate equation I don't know
A shaft carrying a flywheel of diameter 565mm and mass 210 kg is required to run at a speed of 710 rev/min. If the working speed is to be reached in 16 seconds from rest and the coefficient of friction between shaft and bearing is 0.3, determine,
The torque required to overcome inertia and friction .
so far I've worked out T=IA (Torque = Inertia x Angular acceleration), however where is the coefficient of 0.3 involved and how.
any help will be much appreciated Relevant equations
T=Ia ∴ I=(mr²)/2
w2=w1+at ∴ a=(w2-w1)/t
However I'm not sure where the coefficient of friction is involved in all this, maybe a separate equation I don't know