- #1
Amitkumarr
- 20
- 4
- Homework Statement
- A rigid frame in the shape of a right pyramid is made of conducting rods The base ABCD is a square and the apex O is vertically above the centre of the base. The frame is electrically neutral. When it is placed in a uniform electric field of intensity E pointing from the corner A towards the corner D, total charges induced on the rods DC and OC are known to be q1 and q2 respectively. Now the frame is rotated to make the
electric field pointing from the corner A towards the corner C. What are
the charges induced on each rod?
(refer to the attached figure)
- Relevant Equations
- Modulus of induced charge on a conductor is directly proportional to the applied electric field intensity.
Due to symmetry of the system,when the frame is rotated to make the electric field point from corner A to corner C,the magnitude of charges induced on these-(AB,BC,CD,DA),(OA,OC),(OB,OD) will be equal(different for each group but same for elements in these groups).
For the sign of induced charges,if we cut a plane OBD,the rods on left hand side will have negative(-) sign and that on the rods lying on right hand side will be having Positive(+)sign.
But,how do I find the magnitude of induced charges on these rods in terms of q1 and q2 ?Should I apply some superposition principle like electric field along the diagonal is superposition of electric field along the edges?If so,how to proceed further?
Also,what about magnitude of induced charges on rods OB and OD?
For the sign of induced charges,if we cut a plane OBD,the rods on left hand side will have negative(-) sign and that on the rods lying on right hand side will be having Positive(+)sign.
But,how do I find the magnitude of induced charges on these rods in terms of q1 and q2 ?Should I apply some superposition principle like electric field along the diagonal is superposition of electric field along the edges?If so,how to proceed further?
Also,what about magnitude of induced charges on rods OB and OD?