Steady state temperature in a hollow cylinder

In summary, the conversation discusses using cylindrical coordinates to find the temperature formula for a long hollow cylinder with given temperatures on the inner and outer surfaces. The solution involves setting up a Cauchy-Euler equation and a Sturm-Liouville problem with periodic boundary conditions, and the final temperature formula includes standard Fourier coefficients.
  • #1
gophergirl
1
0

Homework Statement


Using cylindrical coordinates rho,phi, and z, let u([rho,phi) denote steady temperatures in a long hollow cylinder a leq rho leq b, -infinity < z < infinity when the temperatures on the inner surface rho= a are f(phi) and the temperature of the outer surface rho = b is zero.

Derive the temperature formula u(rho,phi) = A_{0}(ln b - ln rho)/(ln b - ln a) + summation n = 1 to infinity (a/rho)^n (b^(2n)- rho^(2n))/(b^(2n)- a^(2n)) (A_{n}cos(n*phi) + B_{n}sin(n*phi), where A_{0}, A_{n}, and B_{n} are the standard Fourier coefficients


Homework Equations





The Attempt at a Solution


I've done plenty of boundary value problems for solid cylinders, but never for a hollow one. My textbook offers no examples of hollow cylinders- the only place it appears in the book at all is this homework problem. I can't seem to get beyond setting up the Cauchy-Euler equation, Rho^2R"(rho) + rhoR'(rho) - lambda*R(rho) and the Sturm-Liouville problem Phi"(phi) + lamda*Phi(phi) + 0 with the periodic boundary conditions Phi(-pi) = Phi(pi) and Phi'(-pi) = Phi'(pi).

I think the eigenvalues are the usual ones: lambda_{0} = 0 and lambda_{n} = n^2. That's all the farther I've gotten
 
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  • #2
Using double hash symbols turns

Derive the temperature formula u(rho,phi) = A_{0}(ln b - ln rho)/(ln b - ln a) + summation n = 1 to infinity (a/rho)^n (b^(2n)- rho^(2n))/(b^(2n)- a^(2n)) (A_{n}cos(n*phi) + B_{n}sin(n*phi), where A_{0}, A_{n}, and B_{n} are the standard Fourier coefficients

into

Derive the temperature formula ##u(rho,phi) = A_{0}(ln b - ln rho)/(ln b - ln a) + summation n = 1 to infinity (a/rho)^n (b^(2n)- rho^(2n))/(b^(2n)- a^(2n)) (A_{n}cos(n*phi) + B_{n}sin(n*phi)## , where A_{0}, A_{n}, and B_{n} are the standard Fourier coefficients
 

Related to Steady state temperature in a hollow cylinder

1. What is the steady state temperature in a hollow cylinder?

The steady state temperature in a hollow cylinder refers to the temperature that the cylinder reaches when the heat entering the cylinder is equal to the heat leaving the cylinder. At this point, the temperature remains constant over time.

2. How is the steady state temperature in a hollow cylinder calculated?

The steady state temperature in a hollow cylinder is calculated using the Fourier heat conduction equation, which takes into account the material properties of the cylinder, its dimensions, and the temperature difference between the inside and outside of the cylinder.

3. What factors can affect the steady state temperature in a hollow cylinder?

The steady state temperature in a hollow cylinder can be affected by factors such as the material of the cylinder, its dimensions, the temperature difference between the inside and outside of the cylinder, and the thermal conductivity of the surrounding environment.

4. What is the significance of the steady state temperature in a hollow cylinder?

The steady state temperature in a hollow cylinder is important because it allows us to predict and control the temperature of the cylinder over time. This is useful in various engineering and scientific applications, such as in the design of heat exchangers or in understanding the behavior of materials under different thermal conditions.

5. Can the steady state temperature in a hollow cylinder be lower than the ambient temperature?

Yes, the steady state temperature in a hollow cylinder can be lower than the ambient temperature if the cylinder is being cooled by an external source. For example, in a refrigerator, the steady state temperature of the inner walls of the cylinder will be lower than the surrounding room temperature due to the cooling mechanism.

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