Yes, and that equals the Q = cm∆T lost by the warm lemonade to get to the final temperature.chops369 said:
Specific heat capacity is the amount of heat energy required to raise the temperature of one gram of a substance by one degree Celsius.
Specific heat capacity is measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C) using a calorimeter.
The three main factors that can affect specific heat capacity are the type of substance, its temperature, and its phase (solid, liquid, or gas).
Specific heat capacity is important in many applications, such as cooking, climate control, and industrial processes. It is also used in the study of thermodynamics and heat transfer.
Specific heat capacity is used in various real-life scenarios, such as determining the energy required to heat or cool a substance, designing efficient heating and cooling systems, and calculating the energy needed for chemical reactions or phase changes.