You haven't given any details regarding how you came up with -.822 m/s for the final velocity.mpittma1 said:Homework Statement
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Homework Equations
The Attempt at a Solution
I used ∫Fdt = m(vf-vo)
and came up with -.822 m/s for the final velocity...
I have been reworking this problem over and over and cannot come up with a different answer...
Am i wrong in using the impulse momentum theorem?
Your approach is correct. Can you show us how you integrated? What is the anti-derivative of sin(ωt)?mpittma1 said:Homework Statement
https://scontent-a-sjc.xx.fbcdn.net/hphotos-prn2/t1.0-9/10167935_1403417599934459_6123061969742894932_n.jpg
Homework Equations
The Attempt at a Solution
I used ∫Fdt = m(vf-vo)
and came up with -.822 m/s for the final velocity...
I have been reworking this problem over and over and cannot come up with a different answer...
Am i wrong in using the impulse momentum theorem?
Andrew Mason said:Your approach is correct. Can you show us how you integrated? What is the anti-derivative of sin(ωt)?
AM
SammyS said:You haven't given any details regarding how you came up with -.822 m/s for the final velocity.
Why are you trying to find the final velocity anyway ?
Your integral is correct. I can't tell from your answer how you got the 9e-5 value but it is not correct. The given answer is correct. Remember the argument for cos(ωt) is in radians, not degrees.mpittma1 said:sorry, should have done that from the get go, here is what i did: this is for when t = .55 seconds btw
https://scontent-a-sjc.xx.fbcdn.net/hphotos-prn2/t1.0-9/10001366_1403433926599493_210320460460652531_n.jpg
Andrew Mason said:Your integral is correct. I can't tell from your answer how you got the 9e-5 value but it is not correct. The given answer is correct.
According to your equation:
vf = (1/m)∫Fdt + v0
If you work that out you will get the answer that is given.
AM
mpittma1 said:Worked it out still got v(.55) = -.812 m/s
the answer is suppose to be v(.55) = -.451 m/s
SammyS said:As AM said, ωt is in radians .
Your result looks like your calculator is in degree mode.
Impulse momentum is a concept in physics that describes the relationship between the force applied to an object and the resulting change in its momentum. It is a measure of how much an object's motion changes when a force is applied for a certain amount of time.
Impulse momentum is calculated using the equation I = FΔt, where I is the impulse, F is the force applied, and Δt is the time interval over which the force is applied. This equation can also be written as I = mΔv, where m is the mass of the object and Δv is the change in velocity.
Momentum is a measure of an object's motion, while impulse is a measure of the force that causes a change in an object's momentum. Momentum is a vector quantity, meaning it has both magnitude and direction, while impulse is a scalar quantity, meaning it only has magnitude.
When an impulse is applied to an object, it will cause a change in the object's momentum. This change in momentum will result in a change in the object's velocity, either by increasing or decreasing its speed or changing its direction of motion.
Some examples of impulse momentum in everyday life include hitting a baseball with a bat, kicking a soccer ball, or catching a falling object. In each of these situations, a force is applied for a certain amount of time, resulting in a change in the object's momentum and, therefore, its motion.