- #1
AStupidHippo
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Homework Statement
"In part 2 of the lab you will be firing a water balloon over a tall fence, aiming to hit a target." The fence is 3 meters high. You may fire the balloon from anywhere behind the fence, up to 4 meters away from it: the target will be 20 meters away. Find the angle to shoot the balloon and the stretching distance. There are multiple correct answers.
horizontal distance=s = 20 to 24 meters
mass= .25kg
Spring constant= k= 336.4
spring stretching distance= x = 0 to 25 centimeters
theta=?
Homework Equations
PE + W = KE
PE=.5k x^2
w = Fk * s
Fk = k*x
KE= .5mv^2
The Attempt at a Solution
[/B]Assuming we use all 24 meters
.5(336.4)(x^2) + 24(336.4)(x) = .5(.25)v^2
v= sqrt(2691.2((x^2)/2)+24x)
We're lost after this. Even plugging in a value for x gives us a very large velocity.
For example plugging x=.2 gives a velocity of ~113 m/s. This doesn't seem realistic.