- #1
lumpyduster
- 15
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Homework Statement
So I'm in pchem right now and I haven't taken dif eq (it's not required, but I wish I had taken it now!)
I am asked to solve this differential equation:
y''+y'-2y=0
Homework Equations
I know for a second order differential equation I can solve for the roots first. If there is one root then the solution will take the form y=c1erx+c2xerx
If there are two distinct roots I will get something like:
y=c1er1x+c2er2x
The Attempt at a Solution
I tried to find the roots
r2+r-2=0
r= -2 and r=1
So I get:
y=c1e-2x+c2ex
I am pretty sure this is correct (I checked to see if I got zero if I did y''+y'-2y and I did), but is there a way to find c1 and c2?