RMS of complex waveform (acoustics)

In summary: Where: ##z^\star=a-jb##So: ##|z|^2= z\cdot z^\star = (a+jb)(a-jb) = a^2+b^2##Which is the modulus squared of a complex number.
  • #1
mattattack900
3
0
Hey everyone, just got a quick question in acoustics. I am mainly looking for a mathematical understanding

Homework Statement



Consider two harmonic plane progressive waves of the form

[itex]\tilde{P(x)}[/itex] = [itex]\tilde{A}[/itex]e-jkx

and[itex]\tilde{P(x)}[/itex] = [itex]\tilde{B}[/itex]e+jkx

traveling in opposite directions. Showing all workings, derive expressions for:

1) Total acoustic pressure
2) Total mean squared pressurein the above expressions [itex]\tilde{P(x)}[/itex] represents the acoustic pressure and [itex]\tilde{A}[/itex] and [itex]\tilde{B}[/itex] are complex amplitudes

Homework Equations

The Attempt at a Solution



my solution for part 1 is due to linear superposition:

[itex]\tilde{P(x)}[/itex] = [itex]\tilde{A}[/itex]e-jkx + [itex]\tilde{B}[/itex]e+jkx

i know that the SOLUTION to the second part is:

|[itex]\tilde{P(x)}[/itex]|2 = |[itex]\tilde{A}[/itex]e-jkx|2 + |[itex]\tilde{B}[/itex]e+jkx|2 + 2Re{ [itex]\tilde{A}[/itex][itex]\tilde{B}[/itex]*}cos(kx)

where Re{} denotes the real part ( I couldn't find the actual symbol ), * denotes the complex conjugate and k is the wave number ( k= ω/c )

like i said above i am trying to get a mathematical understanding of the second part. I do not understand how this solution is derived. Thanks
 
Physics news on Phys.org
  • #2
Note: \Re gives ##\Re## ... it's easier to just type out the LaTeX than use the equation editor.

What do the tildas indicate here?

$$\tilde{P}\!_A(x) = \tilde{A}e^{-jkx}\\

\tilde{P}\!_B(x)=\tilde{B}e^{jkx}\\

\tilde{P}(x)=\tilde{A}e^{-jkx}+\tilde{B}e^{jkx}\\$$

You want to understand this:
$$\left | \tilde{P}(x) \right |^2=\left | \tilde{A}e^{-jkx}\right |^2+\left | \tilde{B}e^{jkx}\right |^2 = \left |\tilde{A}\tilde{B}^\star\right | \cos(kx)$$

ABcosθ would normally be a scalar product right - so how does that work if A and B are complex valued?

What happens if you expand the complex amplitudes into ##\tilde{A}=a+jb\; , \; \tilde{B}=c+jd## and expand the exponentials into trig functions?
 
Last edited:
  • #3
Hey, thanks for the reply.

i believe the tilda is the nomenclature used to represent a Complex number.
I will try what you have suggested
 
  • #4
You may not need to though:

If: ##z=a+jb##

Then: ##|z|^2 = a^2+b^2 = z\cdot z^\star ##
 
  • #5
for the question, and great job on attempting the solution for the first part!

The second part of this question is asking for the total mean squared pressure, which is a measure of the average pressure of the complex waveform over time. In order to understand how this solution is derived, we need to break it down step by step.

First, we have the expression for the total acoustic pressure, which is the sum of the two harmonic plane progressive waves traveling in opposite directions. This is known as linear superposition, which states that the total pressure at any point is the sum of the individual pressures at that point.

Next, we have the expression for the total mean squared pressure, which takes into account the magnitude and phase of the complex amplitudes \tilde{A} and \tilde{B}. The squared magnitude of a complex amplitude represents the intensity of the wave, while the phase represents the angle at which the wave is traveling. The squared magnitude is then multiplied by the complex conjugate of the other amplitude, and then multiplied by the cosine of the wave number multiplied by the distance traveled.

This may seem complicated, but it is essentially taking into account the interference patterns of the two waves to find the average pressure over time. I hope this helps to provide a mathematical understanding of the solution.
 

Related to RMS of complex waveform (acoustics)

1. What is RMS of complex waveform in acoustics?

RMS (Root Mean Square) of complex waveform in acoustics is a measure of the average power of a signal over a period of time. It takes into account both the amplitude and frequency of the signal, making it a more accurate representation of the signal's strength compared to other measures such as peak amplitude.

2. How is RMS calculated for a complex waveform?

To calculate RMS, the signal is squared, then the mean (average) is taken over a period of time. The result is then square rooted to obtain the RMS value. This process is done to take into account both the positive and negative values of the signal, resulting in a more accurate measure of the signal's power.

3. What are the benefits of using RMS over other measures of signal strength?

RMS takes into account the whole waveform and provides a more accurate measure of the signal's power. It is also more useful for complex waveforms, such as those found in acoustics, as it considers both the amplitude and frequency components of the signal.

4. Can RMS be used for all types of signals?

RMS is most commonly used for signals that vary over time, such as audio signals in acoustics. It can also be used for other types of signals, such as electrical signals, as long as the signal is varying in a similar manner over time.

5. How is RMS used in acoustics?

In acoustics, RMS is used to measure the power of sound waves, which is important in fields such as noise pollution monitoring and sound engineering. It is also used in the measurement of loudness and in the design of audio equipment to ensure accurate and consistent sound reproduction.

Similar threads

  • Special and General Relativity
Replies
7
Views
1K
Replies
2
Views
733
Replies
4
Views
787
  • Engineering and Comp Sci Homework Help
Replies
6
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
3K
Replies
27
Views
2K
Replies
1
Views
720
  • Differential Equations
Replies
3
Views
1K
Replies
1
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
9
Views
2K
Back
Top