- #1
rishch
- 106
- 1
Homework Statement
1: A decrease in the aperture of a lens changes the
(A)Size of the image
(B)Intensity of the image
(C)Portion of the image
(D) All of these
2: A vessel is filled with two different liquids which do not mix. One liquid is 40cm deep and has n=1.6 and the other is 30cm deep and has n=1.5. What is the apparent depth of the vessel when viewed along the normal?
Homework Equations
1: None
2: n=real depth/apparent depth
The Attempt at a Solution
1: The first ones answer is supposed to be (B)Intensity of the image. I don't know what intensity of an image is though, and I googled it but nothing came up. My answer would've been (C)Portion of the image, but I don't know what that exactly means either, but I'm assuming it means how much of the image you can see, and since the aperture decreases, that should decrease too.
2: This one is really weird an I have no idea how to solve it. The solution is-
n1 = 1.6, d1 = 40 cm
n2 = 1.5, d2 = 30 cm
Apparent depth d = ?
n = real depth (D)/apparent depth (d)
⇒ d = D/n = d1/n1 + d2/n2
d = (25 + 20) cm = 45 cm
But how do they get d = D/n = d1/n1 + d2/n2? They have a video which goes into a bit more detail but I still don't get it :/ Could someone explain?