- #1
agentredlum
- 484
- 0
I have 2 questions about -b and - 4ac in the formula...
x = (-b +-sqrt(b^2 - 4ac))/(2a)
If you are given 2nd degree equations at random (that can be solved using above formula)
Question1: What percent of the equations given would you expect to compute a double negative for -b?
Question2: What percent of the equations given would you expect to compute a triple negative for - 4ac?
For instance if b is -5 then -(-5) must be evaluated, how often would you expect to see 2 negatives?
If a is -2 and c is -3 then - 4(-2)(-3) must be evaluated, how often would you expect to see 3 negatives?
x = (-b +-sqrt(b^2 - 4ac))/(2a)
If you are given 2nd degree equations at random (that can be solved using above formula)
Question1: What percent of the equations given would you expect to compute a double negative for -b?
Question2: What percent of the equations given would you expect to compute a triple negative for - 4ac?
For instance if b is -5 then -(-5) must be evaluated, how often would you expect to see 2 negatives?
If a is -2 and c is -3 then - 4(-2)(-3) must be evaluated, how often would you expect to see 3 negatives?