The current becomes very small and the potential gets larger. Hmm I'm confused on which quantity to look at to determine the power.. Because if current becomes too small, then according to P=IV, power will then decrease. But as resistance increase, potential difference increases too, and again according to P=IV , power will then increase..gneill said:
Yes, you need to consider both quantities if you want to make a choice by logical deduction. Consider V and I when R is at the extremes of its values, say 0 Ω and ∞ Ω.Janiceleong26 said:
I see.. So if R -> ∞ Ω, power decreases, as current decreases right? Ok I got the picture, thanks !gneill said:
Power dissipation in a resistor refers to the amount of energy that is converted into heat when an electric current passes through a resistor. This heat is a result of the resistor's resistance to the flow of current.
Power dissipation in a resistor can be calculated using Ohm's Law, which states that power (P) is equal to the product of voltage (V) and current (I). Therefore, the formula for power dissipation is P = V x I.
Power dissipation is important in a resistor because it determines the maximum amount of current that can safely flow through the resistor without causing damage. It also affects the efficiency and performance of the resistor in a circuit.
The power dissipated in a resistor is directly proportional to its temperature. As more power is dissipated, the temperature of the resistor increases. This can lead to overheating and potentially damage the resistor or other components in the circuit.
The power dissipation in a resistor can be affected by several factors, including the resistance of the resistor, the voltage applied to it, and the ambient temperature. Higher resistance, voltage, or temperature can result in a higher power dissipation.