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Alexander2357
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Homework Statement
You have a circuit with a single resistor of resistance R connected to a battery that has zero internal resistance and has a power output of 12W. A resistor of resistance of 6R is now connected in parallel to the original resistor. How much power is now dissipated in the original resistor?
Homework Equations
Power:
[tex]P = iV = i^{2}R = \frac{V^{2}}{R}[/tex]
Equivalent resistance in parallel:
[tex]\frac{1}{R_{eq}}=\sum_{j=1}^{n}\frac{1}{R_{j}}[/tex]
The Attempt at a Solution
I feel that there isn't enough information in the question to get the required answer.
If the resistors are connected in parallel, then the voltage will be the same across them, but we don't know the voltage of the battery, we only know the power it produces. We also don't know what R is.
Would the power dissipated in the original resistor be changed if we added a second resistor in parallel? Shouldn't it remain the same?
From the given information, is it possible to find the power dissipated in the original resistor?
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