Poisson distribution for insurance

In summary, the insurer uses a Poisson distribution with mean 4 to model the number of warranty claims per month. Each claim results in a payment of $2. The problem asks to find the probability that the total payment in a given month is less than two standard deviations above the average monthly payment. To solve this, we need to define our variables and calculate the mean and standard deviation of the amount paid in claims per month.
  • #1
RAYINDASKY
2
0

Homework Statement



An insurer uses the Poisson distribution with mean 4 as the model for the number
of warranty claims per month on a particular product. Each warranty claim results
in a payment of 2 by the insurer. Find the probability that the total payment by
the insurer in a given month is less than two standard deviations above the average
monthly payment.


Homework Equations





The Attempt at a Solution


So, mean = 4
Standard deviation = 2
x=2

Will I use the density function to solve this?
 
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  • #2
RAYINDASKY said:

Homework Statement



An insurer uses the Poisson distribution with mean 4 as the model for the number
of warranty claims per month on a particular product. Each warranty claim results
in a payment of 2 by the insurer. Find the probability that the total payment by
the insurer in a given month is less than two standard deviations above the average
monthly payment.


So, mean = 4
Standard deviation = 2
x=2

Will I use the density function to solve this?

Mean of what is 2? Standard deviation of what is 2? Where did the 2 come from?

You need to define your variables to get started. If X is the number of warranty claims in a month then the mean of X is 4. What is the std deviation of X? If Y is the amount paid in claims in a month, then isn't Y = 2X? Y and X aren't the same thing. Can you get the mean and std deviation of Y? Can you get going from this?
 

Related to Poisson distribution for insurance

What is a Poisson distribution?

A Poisson distribution is a mathematical probability distribution that is used to model the number of events that occur within a specific time or space interval. It is often used in insurance to predict the frequency of rare events such as accidents or natural disasters.

How is the Poisson distribution used in insurance?

The Poisson distribution is used in insurance to estimate the likelihood of rare events, such as accidents or natural disasters, occurring within a specific time period. This information is then used to calculate the premiums that individuals or businesses must pay for insurance coverage.

What are the assumptions of the Poisson distribution?

The Poisson distribution assumes that the events occur independently of one another, the average rate of events is constant over time, and the probability of an event occurring is proportional to the length of the time interval.

What is the mean and variance of a Poisson distribution?

The mean of a Poisson distribution is equal to the rate parameter λ, which represents the average number of events per time or space interval. The variance of a Poisson distribution is also equal to λ.

How can the Poisson distribution be applied in insurance risk management?

The Poisson distribution can be used in insurance risk management to assess the potential risks and losses associated with different types of events. By understanding the frequency and severity of these events, insurance companies can adjust their premiums and policies to mitigate risk and ensure profitability.

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