One-Dimensional Motion with Constant Acceleration

In summary, the question asks for the distance traveled by a rock dropped from the top of a high cliff, with a downward acceleration of g and no air friction. The formula used is X=Xo+VoT+1/2AT^2, where X is the final position, Xo is the initial position, Vo is the initial velocity, A is the acceleration, and T is the time. The initial position is not given, but it can be chosen as 0 at the top of the cliff. The initial velocity is 0 as the rock is released from rest. The acceleration due to gravity can be taken as either positive or negative, as long as the results are interpreted correctly. Therefore, the mountain is not a factor
  • #1
PhysicallyAbel
26
1

Homework Statement


A rock is released from rest from the top of a very high cliff, and accelerates downward at g.
Approximately how far does the rock travel in the first 7 seconds of its free-fall? (Assume no air friction.)

Homework Equations


X=Xo+VoT+1/2AT^2

The Attempt at a Solution


I understand how to work out the problem, but I do not know why it works. You simply substitute the numbers into get the distance. But for some reason, you are not given (nor do you use) initial position like the equation calls for. Can someone explain why it's simply thrown away? The initial position can't be 0, as it's being dropped from a mountain.[/B]
 
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  • #2
PhysicallyAbel said:

Homework Statement


A rock is released from rest from the top of a very high cliff, and accelerates downward at g.
Approximately how far does the rock travel in the first 7 seconds of its free-fall? (Assume no air friction.)

Homework Equations


X=Xo+VoT+1/2AT^2

The Attempt at a Solution


I understand how to work out the problem, but I do not know why it works. You simply substitute the numbers into get the distance. But for some reason, you are not given (nor do you use) initial position like the equation calls for. Can someone explain why it's simply thrown away? The initial position can't be 0, as it's being dropped from a mountain.[/B]

The question is asking how far the rock travels. That's the difference between the final position and the initial position. ##x_0## cancels when you take the difference.
 
  • #3
It sounds like you are memorizing formulas without really understanding them. That's a bad idea. You are free to take the "0" point any where you want. I suggest taking x= 0 at the top of the cliff. Further, the fact that rock is "released from rest" tells you that the initial velocity is 0. Finally, you can take the acceleration due to gravity to be either negative or positive- as long as you interpret the results in the same way- you are free to choose "positive" or "negative" either up or down.
 
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Likes Chestermiller
  • #4
You can ignore the mountain altogether : you have a ( constant ) acceleration rate, a starting velocity (u = 0) and a time ( 7 seconds ), so use Newtons rules of motion.
 

Related to One-Dimensional Motion with Constant Acceleration

What is one-dimensional motion with constant acceleration?

One-dimensional motion with constant acceleration is a type of motion where an object moves along a straight line with a constant rate of change in its velocity. This means that the object's acceleration remains constant throughout its motion.

What is the equation for one-dimensional motion with constant acceleration?

The equation for one-dimensional motion with constant acceleration is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

What is the difference between average velocity and instantaneous velocity?

Average velocity is the total displacement of an object divided by the total time taken, while instantaneous velocity is the velocity of an object at a specific moment in time. Average velocity can be calculated for a whole journey, while instantaneous velocity can vary throughout the journey.

How does acceleration affect an object's motion?

Acceleration affects an object's motion by changing its velocity. If an object is accelerating, its velocity will either increase or decrease depending on the direction of the acceleration. If the acceleration is in the same direction as the velocity, the object's speed will increase. If the acceleration is in the opposite direction, the object's speed will decrease.

How does the motion of an object change when the acceleration is zero?

When the acceleration is zero, the object's velocity remains constant. This means that the object will continue to move at the same speed and in the same direction. The object's motion will not change unless a force is applied to it, causing its acceleration to change.

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