- #1
DumSpiroSpero
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Homework Statement
A block of mass ## m ##, attached to a rope, is dropped at the point A.
When the block reaches the point B, the tension is ## T = 2 \cdot m \cdot g ## and the rope broke at that same point.
If the length of the rope is ## L = 6cm ##, evaluate the height ## h ## where the rope broke.
Homework Equations
The solution's manual uses mechanical energy and the centripetal force ( ## T - m \cdot g \cdot sin\theta = \frac{m \cdot v^{2}}{2} ##). Since ## h = sin \theta \cdot L##, we find the height ## h = 4cm ##.
The Attempt at a Solution
I understand and agree with that solution, but I can't figure out why my solution is wrong.
Since ## W = m \cdot g ## is perpendicular to the horizontal line, we have a vectorial triangle composed by ## \vec{T}, \vec{W}, \vec{F}## (the green, red and purple vectors in the figure below, respectively), where F is the resultant force of T and W, i.e. ## \vec{F} = \vec{T} + \vec{P}## .
In this triangle, we have ## sin \theta = \frac{W}{T} = \frac{W}{2\cdot W} = \frac{1}{2}## and ##sin \theta = \frac{h}{L}##. Therefore, ## h = \frac{L}{2} = 3cm ##. I couldn't find my mistake.