- #1
blainiac
- 50
- 2
Hello everyone!
I was wanting to know if something like this was possible. I read (Wikipedia) that the moment a cylinder will burst is when the hoop stress is equal to the cylinder's tensile strength. It also appears that the thickness of the material doesn't matter. I don't see Young's Modulus being used here either.
If I had a thin fiberglass (ρ = 1850 kg/m^3, σ = 260 MPa) disk 0.5 m in radius, it appears ~7,159 RPM is the max before bursting.
Questions:
1) Is this the correct equation to use for finding the burst speed?
2) Is there a definitive material properties sheet online to ensure I'm using the correct numbers?
3) Is there a good 'safe' percentage of the burst speed (like factor of safety) to stay under while operating something like this?
I was going to study the boundary layer on a rotating disk at high rotational speeds, and wanted to be safe before setting everything up.
I was wanting to know if something like this was possible. I read (Wikipedia) that the moment a cylinder will burst is when the hoop stress is equal to the cylinder's tensile strength. It also appears that the thickness of the material doesn't matter. I don't see Young's Modulus being used here either.
If I had a thin fiberglass (ρ = 1850 kg/m^3, σ = 260 MPa) disk 0.5 m in radius, it appears ~7,159 RPM is the max before bursting.
Questions:
1) Is this the correct equation to use for finding the burst speed?
2) Is there a definitive material properties sheet online to ensure I'm using the correct numbers?
3) Is there a good 'safe' percentage of the burst speed (like factor of safety) to stay under while operating something like this?
I was going to study the boundary layer on a rotating disk at high rotational speeds, and wanted to be safe before setting everything up.