Burst/Rupture Disk Capacity - Experimental vs. Theoretical

In summary, the bore for the burst disk is 2" and the material is Brass 260 H02 (1/2 Hard). The disks are solid and flat (i.e. no scoring or features to promote a certain type of failure). The only thing that varies is the thickness of the disks, and that determines the bursting pressure. I found the theoretical thicknesses to be very high just based on intuition and a couple papers I've seen about burst disks. I also did some quick FEA in Solidworks, and the results mostly agreed with my calculations. We considered all of this and used much thinner disks when we started actual testing/calibration. After the initial testing, we found we needed much thinner burst disks (comp
  • #1
jstluise
58
0
We have built a cold gas cannon that utilizes burst disks as the means to quickly release the built up pressure with maximum flow. The bore for the burst disk is 2" and the material is Brass 260 H02 (1/2 Hard). The disks are solid and flat (i.e. no scoring or features to promote a certain type of failure). The only thing that varies is the thickness of the disks, and that determines the bursting pressure.

In calculating the theoretical bursting pressures, I found this problem to be exactly like the "circular plate, uniform load, edged clamped" as seen on this website: (http://www.roymech.co.uk/Useful_Tables/Mechanics/Plates.html). As expected, the max stress occurs at the edges of the plate.

I calculated the theoretical disk thicknesses based on the bursting pressures we want to use. I found the theoretical thicknesses to be very high just based on intuition and a couple papers I've seen about burst disks. I also did some quick FEA in Solidworks, and the results mostly agreed with my calculations. We considered all of this and used much thinner disks when we started actual testing/calibration.

After the initial testing, we found we needed much thinner burst disks (compared to theoretical) to achieve the bursting pressures we wanted. Here is a plot comparing experimental to theoretical:

qSJH7Zs.jpg


I saw on the website it says, "The equations are only valid if the deflection is small compared to the plate thickness." I thought this might be my problem but my calculated defection is only 10-20% of my plate thickness. Maybe that is still too big.

Does anyone have some thoughts on why the two do not agree?
 
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  • #2
I would guess your deflections are many times your disc thickness at rupture pressure. Have you (safely) observed the amount of disc bulge prior to bursting?
 
  • #3
insightful said:
I would guess your deflections are many times your disc thickness at rupture pressure. Have you (safely) observed the amount of disc bulge prior to bursting?

Thanks for the response. We have not observed the burst disk prior to bursting; we keep a very safe distance with proper barricading.

After thinking about it a bit more, I'm convinced that the equations I referenced are only valid up to yield. At one point we performed a leakdown test by using a very thick piece of brass (0.040") and bringing the pressure chamber up to 400 psi. After the test, even the thick disk was visibly deformed (very slight bulge). According to the equations, the max stress with t=0.040" and p=400 psi is around 187 ksi, which is much higher than the yield strength of the material (52 ksi). So, the disk did yield as the equations said it would, but there was not failure even though the ultimate strength of the brass is around 62 ksi.

After the disk yields some, I'm sure the deflection is more than the thickness of the disk, so the equations are invalid after that point. I can accept that. And, I'm not complaining about finding out these values experimentally either :) Here are the remnants of a 0.005" disk.

rJ59djE.jpg
 
  • #4
Neat photo. I have observed bulging lids and bottoms on 55 gal drums and specified many rupture discs. There's a lot of art and trial and error in rupture disc design. I assume that once your disc deforms some, you have a brass "balloon" and are in a different stress regime.
 

Related to Burst/Rupture Disk Capacity - Experimental vs. Theoretical

What is the difference between experimental and theoretical burst/rupture disk capacity?

Theoretical burst/rupture disk capacity refers to the calculated maximum pressure that a disk can withstand before rupturing, based on its material properties and dimensions. Experimental burst/rupture disk capacity, on the other hand, is determined through physical testing of the disk under various conditions.

Which measurement is more accurate, experimental or theoretical burst/rupture disk capacity?

In general, experimental burst/rupture disk capacity is more accurate because it takes into account real-world variables such as temperature, pressure, and material imperfections. Theoretical calculations are based on ideal conditions and may not always reflect the actual performance of the disk.

What factors can affect the burst/rupture disk capacity of a disk?

The burst/rupture disk capacity of a disk can be affected by factors such as material properties, disk dimensions, temperature, pressure, and installation method. These factors can vary from disk to disk and may impact the disk's performance under different conditions.

How is the experimental burst/rupture disk capacity of a disk determined?

The experimental burst/rupture disk capacity of a disk is determined by subjecting the disk to increasing pressure until it ruptures. The pressure at which the disk ruptures is recorded and compared to the theoretical burst/rupture disk capacity to determine the disk's performance.

Why is it important to know the burst/rupture disk capacity of a disk?

The burst/rupture disk capacity is an important factor to consider in the design and use of a disk. It ensures that the disk can withstand the expected pressure and prevents overpressure situations that could lead to equipment damage or safety hazards. Knowing the burst/rupture disk capacity also allows for proper sizing and selection of the disk for a specific application.

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