Linear equations - use of integrating factor

[nufc365]

Hi, I am doing self study and have hit a snag in the road. Can someone please clarfiy this for me. I am reading K.A. Stroud's Engineering Mathematics which so far has been great.


Consider the equation [itex]\frac{dy}{dx}[/itex] + 5y = e^2x

In this case, we begin multiplying both sides by e^5x. This gives

e^5x[itex]\frac{dy}{dx}[/itex] + y5e^5x = e^2x.e^5x = e^7x

We now find that the left-hand-side is the derivative of y.e^5x.

[itex]\frac{d}{dx}[/itex](y.e^5x) = e^7x


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Can someone please clarify how the left hand side is the derivative of y.e^5x.

I get that y5e^5x is the derivative of y.e^5x, but what about the first part of the left-hand-side. What happens to the e^5x[itex]\frac{dy}{dx}[/itex]

 

[nufc365]

Just read the sticky, my apologies. I have posted this question over in homework and questions if anyone would be kind enough to answer.

https://www.physicsforums.com/showthread.php?t=654435