Integrate that by parts for integral

In summary, the formula for integration by parts is ∫u dv = uv - ∫v du, and u and dv should be chosen strategically. The purpose of using this method is to simplify the integration of a product of two functions, and there are specific rules and guidelines to follow. Integration by parts can also be used for definite integrals, but the limits must be applied to each term in the equation.
  • #1
fiziksfun
78
0
i need help taking this integral

[tex]\int[/tex] 9sin[tex]\sqrt{t+1}[/tex]


help please! i don't even know where to start :[
 
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  • #2
First write it correctly:
[tex]\int 9 sin(\sqrt{t+1}) dt[/tex]

Make the obvious substitution [itex]u= \sqrt{t+1}= (t+1)^{1/2}[/itex] so that [itex]du= (1/2)(t+1)^{-1/2}dt[/itex] or 2udu= dt.
(Equivalently, u2= t+ 1.)

That changes your integral to
[tex]9\int u sin(u)du[/tex]
and you can integrate that by parts.
 
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Related to Integrate that by parts for integral

What is the formula for integration by parts?

The formula for integration by parts is ∫u dv = uv - ∫v du, where u is the first function and dv is the differential of the second function.

How do you choose which function to be u and which to be dv?

When using integration by parts, the function u should be a function that becomes simpler when differentiated, while dv should be a function that becomes easier to integrate when differentiated.

What is the purpose of using integration by parts?

The purpose of using integration by parts is to simplify the integration of a product of two functions by breaking it down into simpler components.

Are there any specific rules or guidelines for using integration by parts?

Yes, there are a few guidelines to follow when using integration by parts. These include choosing u and dv strategically, using the formula correctly, and considering the choice of u and dv to be final (no switching back and forth).

Can integration by parts be used for definite integrals?

Yes, integration by parts can be used for definite integrals. The formula remains the same, but the limits of integration must also be applied to each term in the equation.

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