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cwbullivant
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EDIT: Problem found. This thread can now be ignored.
Find the indefinite integral.
((y^2-1)/y)^2 dy
I've attempted a few things. I first attempted to split the statement inside the outer parentheses into two fractions;
(y^2/y - 1/y)^2 dy
Then to reduce it to,
(y - 1/y)^2 dy
And then foil it and take an antiderivative. This comes out to
Foiled: y^2 - 2 + 1/y^2 dy
And then the antiderivative:
y^3/3 - 2y + 1/y + C
But I appear to still be incorrect. According to Wolfram's integral calculator, the solution is
y^3/3 - 2y - 1/y
I'm close. I'm apparently missing a sign somewhere, and I can't seem to find where it is, and I don't feel comfortable plugging in the answer until I know how I got there.
Homework Statement
Find the indefinite integral.
Homework Equations
((y^2-1)/y)^2 dy
The Attempt at a Solution
I've attempted a few things. I first attempted to split the statement inside the outer parentheses into two fractions;
(y^2/y - 1/y)^2 dy
Then to reduce it to,
(y - 1/y)^2 dy
And then foil it and take an antiderivative. This comes out to
Foiled: y^2 - 2 + 1/y^2 dy
And then the antiderivative:
y^3/3 - 2y + 1/y + C
But I appear to still be incorrect. According to Wolfram's integral calculator, the solution is
y^3/3 - 2y - 1/y
I'm close. I'm apparently missing a sign somewhere, and I can't seem to find where it is, and I don't feel comfortable plugging in the answer until I know how I got there.
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