- #1
HelloMrCo
- 7
- 0
Homework Statement
A spherical brass shell has an interior volume of 1.60 x 10-3m^3. Within this interior volume is a solid steel ball that has a volume of 0.70 x 10-3m^3. The space between the steel ball and the inner surface of the brass shell is filled completely with mercury. A small hole is drilled through the brass, and the temperature of the arrangement is increased by 12 celsius degree. What is the volume of the mercury that spills out of the hole?
Homework Equations
Delta V = B*Vo*Delta t
The Attempt at a Solution
Delta V(Mercury) = 3.49e-6 m^3
Delta V(Brass) = 1.09e-6 m^3
Delta V(Steel) = 3.02e-7 m^3
I've already computed for all of the changes in volume for the two spheres and the mercury. I'm having a problem on how to solve for the spillover because from our previous examples there are no spherical containers.