JazzyJones said:Homework Statement
does anyone know how to solve this equation for just x?
x + x^2 = a^2*b^2 - 2.01j - j^2 - 15.132
it's possible right? because I'm trying to solve for four variables using four equations but two of my variables will have a first plus a second degreeThe Attempt at a Solution
my original equation was in the form [((x-h)^2)/a^2] + [((y-k)^2)/b^2] = 1
i am trying to solve for h, k , a, b
JazzyJones said:does anyone know how to solve this equation for just x?
x + x^2 = a^2*b^2 - 2.01j - j^2 - 15.132
my original equation was in the form [((x-h)^2)/a^2] + [((y-k)^2)/b^2] = 1
i am trying to solve for h, k , a, b
Dick said:For the first equation, sure you can solve for x. Completing the square is probably the easiest way. But I don't see what the first equation has to do with the second one and you certainly can't solve the second one for the four variables h,k,a,b. You only have one equation.
JazzyJones said:I have x and y values. I plug the four different coordinates into the second equation and get four equations. Then I solve using quadratic for h and k, (a and b can be solved without quadratic I believe). Then start plugging them into one equation at a time correct?
Dick said:Sounds pretty hard though.
JazzyJones said:Yea, I'm aware of that :D
Vadar2012 said:Would be nice to see all 4 equations. You can't just put them into a matrix form and solve a^-1*b = c?
what do you mean solve it by Newtonian??Vadar2012 said:I'd just write a code to solve it by Newtonian or something. Doing it by hand it just too much effort and too much room for error. All that substitution is just asking for problems.
Solving for four variables when two have first and second degrees requires the use of a system of equations. You will need to have at least four equations to solve for four variables.
The first step is to identify the variables and their degrees in each equation. This will help you determine how many equations you need to solve for all four variables.
It depends on the specific equations you are working with. Substitution may be more useful when the equations are simpler, while elimination may be more effective when the equations are more complex. It is best to try both methods and see which one leads to a solution.
Yes, a graphing calculator can be a helpful tool in solving for four variables when two have first and second degrees. You can enter the equations into the calculator and use the graphing function to find the point of intersection, which represents the solution.
If you end up with more than one solution, it means that the equations are not independent and there are multiple ways to solve for the variables. You can check your work and see if there are any errors, or you can try using a different method of solving, such as substitution or elimination, to see if you get a different solution.