- #1
Heyxyz
- 8
- 3
- Homework Statement
- A box weighing 2 kg falls onto a spring with a constant of 300 N/m. How long does the box touch the spring?
- Relevant Equations
- T = 2π * √(m/k)
T = 2π * √(2/300), T = .513 seconds.
If I divide it by 4/3, I get a final answer of .385 seconds of touch.
I know the box isn't attached for the entire oscillation, so T has to be divided. To me, it makes sense to divide it by 4/3 (when the box falls, the spring is compressed, hits equilibrium, and the launches the box... 3 out of 4 steps), but I've heard that dividing it by 2 is correct. Of course, I could be totally off, and this could be some sort of kinematic problem.
Thank You!
If I divide it by 4/3, I get a final answer of .385 seconds of touch.
I know the box isn't attached for the entire oscillation, so T has to be divided. To me, it makes sense to divide it by 4/3 (when the box falls, the spring is compressed, hits equilibrium, and the launches the box... 3 out of 4 steps), but I've heard that dividing it by 2 is correct. Of course, I could be totally off, and this could be some sort of kinematic problem.
Thank You!
Last edited by a moderator: