How Fast Must a Basketball Player Jump to Reach 85.8 cm?

[adad22]

A 92.7 kg basketball player can leap straight up in the air to a height of 85.8 cm. The player bends his legs until the upper part of his body is dropped by 64.0cm, then he begins his jump. With what speed must the player leave the ground to reach a height of 85.8 cm?

The mass is given for the next part of the question which switches to dynamics, or at least that is my assumption. I can not seem to solve for the initial velocity as he leaves the ground because his height is not given nor the time it takes to reach the top or anything else for that matter. I can do the 2nd part on my own if only i could get this first part.

I think I am missing something obvious, any help is greatly appreciated.
-Adrian

 

[adad22]

THank you for moving

 

[m2003]

I understand your confusion and frustration with this problem. It seems like there are missing pieces of information that are necessary to solve for the initial velocity of the basketball player. In order to accurately calculate the initial velocity, we would need to know the player's height, the duration of their jump, and the acceleration due to gravity. Without these values, it is impossible to accurately solve for the initial velocity.

I would suggest reaching out to the source of the problem and asking for clarification or additional information. In science, it is important to have all the necessary data in order to make accurate calculations and conclusions. Without all the information, any solution would be based on assumptions and could lead to incorrect results.

In the meantime, you could also try setting up a range of possible scenarios and calculate the initial velocity for each one to see if any of them match the given height of 85.8 cm. This could give you an idea of the possible range of values for the initial velocity, but it would not be a definitive answer without all the necessary information.

I hope this helps and good luck with your problem-solving!