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CJ256
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Homework Statement
What is the rate of change of an area of a square with respect to the length of its diagonal (r) when the square has a side length of 5 meters?
Homework Equations
The Attempt at a Solution
Area of a square = s^2
and if Area of a square = s^2 then it would = (r^2)/2
Pythagorean Theorem to find the diagonal of the square:
r^2 = s^2 + s^2
r^2= 2s^2
r=sqrt2s^2
r=sqrt2 * s
and then I did this:
(dA)/(dr) and since we need A in terms of r (i hope that's what the question is asking)
then ((d)/(dr))((r^2)/(2)) = (2r)/2 = r
so then the final answer that I got is A = (5^2)/2 = 12.5