How Can I Simplify This Integral Using Long Division?

In summary, the integral can be simplified to $6\int_{}^{}u^2 + u + 1 + \frac{1}{u - 1}\,du$ by using long division to simplify the fraction $\frac{u^3-1}{u-1}$.
  • #1
tmt1
234
0
I have this integral

$$6\int_{}^{} \frac{u^3 - 1 + 1}{u - 1}\,d$$

And I need to simplify it to

$$6\int_{}^{}u^2 + u + 1 \frac{1}{u - 1}\,du$$

But I don't know how to get to this step.
 
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  • #2
The crucial step here is to simplify:

\(\displaystyle \frac{u^3-1}{u-1}\)

What happens if you factor the numerator as the difference of cubes?
 
  • #3
tmt said:
I have this integral

$$6\int_{}^{} \frac{u^3 - 1 + 1}{u - 1}\,d$$

And I need to simplify it to

$$6\int_{}^{}u^2 + u + 1 + \frac{1}{u - 1}\,du$$

But I don't know how to get to this step.

How about Long Division?

[tex]\begin{array}{cccccccccc}
& & & & u^2 & +& u &+& 1 \\
& & - & - & - & - & - & - & - \\
u-1 & ) & u^3 \\
& & u^3 & - & u^2 \\
& & - & - & - \\
& & & & u^2 \\
&&&& u^2 &-& u \\
&&&& -&-&- \\
&&&&&& u \\
&&&&&& u &-& 1 \\
&&&&&& - & - & - \\
&&&&&&&& 1
\end{array}[/tex][tex]\text{Therefore: }\;\frac{u^3}{u-1} \;=\;u^2 + u + 1 + \frac{1}{u-1} [/tex]
 

Related to How Can I Simplify This Integral Using Long Division?

What is an integral?

An integral is a mathematical concept that represents the area under a curve. It is used in calculus to find the value of a function over a certain interval.

Why do we need to simplify integrals?

Simplifying integrals makes them easier to solve and allows us to find the exact value of the integral without having to use complex methods. It also helps us to better understand the behavior of the function.

What are the steps to simplify an integral?

The steps to simplify an integral include using the properties of integrals, such as linearity and power rule, to rewrite the integral in a simpler form. Then, you can use substitution or integration by parts to further simplify the integral.

When should we use substitution to simplify integrals?

Substitution is useful when the integral contains a complicated expression or when the limits of integration are difficult to work with. It allows us to replace the variable in the integral with a new variable, making it easier to solve.

What is integration by parts and how is it used to simplify integrals?

Integration by parts is a method used to simplify integrals that involve the product of two functions. It involves using the product rule of derivatives to rewrite the integral in a simpler form. This method is useful when the integral cannot be solved by other methods, such as substitution or using properties of integrals.

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