- #1
robax25
- 238
- 3
Hi, I have a problem to design traktor power transmission.Can anybody tell me How to calculate minimum speed for output shaft.I need to calculate number of rotation(maximum and minimum) of the driven shaft
Here is the equation: n(driven) max=(n(drive) + n2 (max). (z3/z1)) /(z3/z2 +1)
so I get 2500 rpm
n(driven) min=(n(drive) + n2 (min). (z3/z1)) / (z3/z2 +1)
So I need to get n2 mimimum value. Here is given only n2max but n2(min) is not given.How can I calculate the n2 min value?
I tried to calculate and get n2(min)= 1875 rpm but it should be 2000 rpm.
Here is the formula,
n(motor)/n(pump)=V(pump) / V(motor)
At the end, the minimum driven shaft rotation is 1437.5rpm but it should be 1500 rpm
Here is the equation: n(driven) max=(n(drive) + n2 (max). (z3/z1)) /(z3/z2 +1)
so I get 2500 rpm
n(driven) min=(n(drive) + n2 (min). (z3/z1)) / (z3/z2 +1)
So I need to get n2 mimimum value. Here is given only n2max but n2(min) is not given.How can I calculate the n2 min value?
I tried to calculate and get n2(min)= 1875 rpm but it should be 2000 rpm.
Here is the formula,
n(motor)/n(pump)=V(pump) / V(motor)
At the end, the minimum driven shaft rotation is 1437.5rpm but it should be 1500 rpm
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