- #1
beaf123
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< Mentor Note -- thread moved to HH from the technical math forums, so no HH Template is shown >
Hi, I have already delivered the homework so my reason for asking is because I want to/ need to understand it.
I am at question d. I have found the two differential equations.
They are:
c° = -1/0,5 * ( f'(k) - 0,04)Ct
and
k° = f(k)-0,06kt -Ct
In equilibrium both c° and k° will be zero so both equations can be set equal to zero.
But how do you proceede from here, to find k* and c*? Can you set f'(k) = 0,25K^-0,75 + 2 since f(k) = k^0,25 and k(0) = 2?
If I have explained it too bad I can elaborate. I hope someone can help me:)
Hi, I have already delivered the homework so my reason for asking is because I want to/ need to understand it.
I am at question d. I have found the two differential equations.
They are:
c° = -1/0,5 * ( f'(k) - 0,04)Ct
and
k° = f(k)-0,06kt -Ct
In equilibrium both c° and k° will be zero so both equations can be set equal to zero.
But how do you proceede from here, to find k* and c*? Can you set f'(k) = 0,25K^-0,75 + 2 since f(k) = k^0,25 and k(0) = 2?
If I have explained it too bad I can elaborate. I hope someone can help me:)
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