- #1
raininggently
- 2
- 0
Homework Statement
What will be the equilibrium temperature when a 245-g block of copper at 285° c is placed in a 145 g aluminium calorimeter cup containing 825 g of water at 12°c?
Homework Equations
q=mcΔt
qlost+qgained=0
-qlost=qgained
-m1c1t1=m2c2t2
The Attempt at a Solution
So this is what I did so far:
Know :
Copper Aluminium
- 245 g= 0.245 kg - 145 g= 0.145 kg
- specific heat capacity of copper = 0.385 j kg - ti=12°c
- ti ( Inital temp)= 285°c -teq=?
-teq=?
Water
-825 g=0.825 kg
-ti=12°c
-teq=? ( T equilibrium )
So I know qlost+ qgained= 0
then - qlost=qgained.
In this case the qlost will be the copper.
So this is what I used: ( Cu- copper; al-aluminium; & w- water)
Mcu(Ccu)(Ticu-Teq)=Mal(Cal)(Teq-Ti) + Mw(Cw)(Teq-ti)
(0.245 kg)(0.385)(285°c-Teq)=(0.145 kg)(9.2x10^2)(Teq-12°c)+(0.825kg)(4.18x10^3)(teq-12°c)
Now when I come to this, I have no clue what to do :
(0.094325)(285°c-Teq)=(133.4)(Teq-12°c)+(3448.5)(teq-12°c)
Please let me know what I`m doing wrong, and how i can solve it completely.