- #1
utkarshakash
Gold Member
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Homework Statement
If [itex] \displaystyle \int_0^1 \dfrac{e^t}{t+1} dt = a[/itex] then [itex]\displaystyle \int_{b-1}^b \dfrac{e^{-t}}{t-b-1} dt [/itex] is equal to
Homework Equations
The Attempt at a Solution
I used the definite integral property in the second integral
[itex]\displaystyle \int_{b-1}^b \dfrac{e^{-2b-1-t}}{b-2-t} dt [/itex]