Find Focus of Parabola: y:-(1/4)x^2 + 2x - 5

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In summary, the conversation discussed finding the focus of a parabola and provided different definitions for the focus. It also mentioned that the focus can be determined using polar coordinates or by writing the quadratic equation in a form similar to the standard form.
  • #1
bengaltiger14
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Homework Statement



Find the focus of parabola: y:-(1/4)x^2 + 2x - 5

The Attempt at a Solution



Multiplying by 4 to get rid of fraction I get:
4y:-x^2 + 2x - 5

I will bring over the -5:
4y+5:-x^2 +2x

Completing Square I obtain:

4y+6:-(x-1)^2


Is all this correct thus far?
 
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  • #2
Do you know what a focus of a parabola is? I think it has something to do with polar coordinates.
 
  • #3
The focus is the central point of a parabola I believe. It determines if parabola points up or down
 
  • #4
bengaltiger14 said:
The focus is the central point of a parabola I believe. It determines if parabola points up or down
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.
 
  • #5
Irid said:
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.

All very true. But you don't NEED polar coordinates. If you write a standard form for the parabola in cartesian coordinates x^2=4ay the vertex is at the origin and the distance from vertex to focus is 'a'. You just have to write your quadratic in a form similar to the standard form. Like (x-x0)^2=4a(y-y0). Now you have vertex at (x0,y0) and distance to focus 'a'.
 

Related to Find Focus of Parabola: y:-(1/4)x^2 + 2x - 5

1. What is the focus of the parabola?

The focus of any parabola is a point that lies on the axis of symmetry and is equidistant from the directrix. In the equation y = -(1/4)x^2 + 2x - 5, the focus can be found by using the formula (h, k) = (-b/2a, c - b^2/4a), where h and k are the coordinates of the focus.

2. How do you find the axis of symmetry of a parabola?

The axis of symmetry of a parabola is a vertical line that passes through the vertex and divides the parabola into two equal halves. In the equation y = -(1/4)x^2 + 2x - 5, the axis of symmetry can be found by using the formula x = -b/2a, where b is the coefficient of the x-term and a is the coefficient of the x^2 term.

3. What is the directrix of a parabola?

The directrix is a horizontal line that is perpendicular to the axis of symmetry and is located on the opposite side of the focus. In the equation y = -(1/4)x^2 + 2x - 5, the directrix can be found by using the formula y = c - b^2/4a, where c is the constant term in the equation.

4. How do you graph a parabola using its equation?

To graph a parabola, you can use the equation y = ax^2 + bx + c, where a, b, and c are constants. Begin by plotting the vertex, which can be found using the formula (-b/2a, c - b^2/4a). Then, plot points on either side of the vertex by using different values of x and solving for y. Connect the points to create a smooth curve, and use the axis of symmetry to ensure that the parabola is symmetrical.

5. Can the focus of a parabola be outside of the parabola?

No, the focus of a parabola will always lie on the parabola or inside the parabola. If the focus were to fall outside of the parabola, it would no longer be considered a focus and would not meet the definition of a parabola.

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