- #1
knowLittle
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Homework Statement
## f\left( x,y\right) =x^{2}-4xy+6x-8y+2y^{2}+10 ##
## f_{x}=2x-4y+6=0 ##
## f_{y}=-4x-8+4y=0 ##
## f_{y}=-4\left( x-y+2\right) ##
-2=x-y, then solving fx and using this equality
## f_{x}=0=2\left( x-2y+3\right) =0 ##
2(-2 -y+3)=0
2(1-y)=0
y=1, then pluggin it to values
-2=x-y
-2=x-1
-1=x, So critical points at (-1,1)
fxx(-1,1)fyy(-1,1)-0^2=8, which is greater than zero and fxx is too. Therefore, there is a global minima at (-1,1)
There is no saddle point or global maxima?
Homework Equations
The Attempt at a Solution
Is this correct?