# Filtration of a probability space

#### gnob

##### New member
Hi again, I hope you can clarify me on this:

Consider a probability space $(\Omega,\mathcal{F},\mathbb{P})$ and let $\{\mathcal{F}_t\}_{0\leq t<\infty}$ be a filtration on it. Define
$\mathcal{F}_{\infty} = \sigma\left(\bigcup_{t} \mathcal{F}_t \right)$ where $t \in [0,\infty).$

My question: Is $\mathcal{F}_{\infty} = \mathcal{F}$?

I came across with an answer that it is not, but I forgot the source nor I remember if there is a counterexample. Can anyone please help me? Thanks. Please also give me some reference on it.

Thanks, thanks, thanks...

#### girdav

##### Member
If in the definition of filtration we don't assume strict inclusion we get a counter example taking $\mathcal F_t=\mathcal G$, where the latest is a strictly contained $\sigma$-algebra.