Epsilon-delta definition and continuity at a point

[jameswill1am]

Homework Statement

Show that the following equation is continuous using the epsilon-delta definition at y=-2

Homework Equations

[tex]\f(y)=\sqrt[3]{y+3}[/tex]

The Attempt at a Solution

so i got to a stage where;

[tex]\frac{1}{\left|\left(\sqrt[3]{y+3}\right)^{2}+\sqrt[3]{y+3}+1\right|}\times\left|y-c\right|[/tex]

but this is where i always get stuck on these things. I just don't know where to start with picking my delta. If anyone could explain the best way of going about it that would be very helpful.

Thanks

p.s. i didn't type out the whole extent of my solution so far. Hopefully its ok so far but let me know if that bit is wrong as well.

 

[Mark44]

I revised your LaTeX so that it would render as you wanted it to.

Homework Statement

Show that the following equation is continuous using the epsilon-delta definition at y=-2

Homework Equations

[tex]f(y)=\sqrt[3]{y+3}[/tex]

The Attempt at a Solution

so i got to a stage where;

[tex]\frac{1}{\left|\left(\sqrt[3]{y+3}\right)^{2}+\sqrt[3]{y+3}+1\right|}\times\left|y-c\right|[/tex]

but this is where i always get stuck on these things. I just don't know where to start with picking my delta. If anyone could explain the best way of going about it that would be very helpful.

Thanks

p.s. i didn't type out the whole extent of my solution so far. Hopefully its ok so far but let me know if that bit is wrong as well.

I think I understand what you're doing, with the idea being that (a - b)(a² + ab + b²) = a³ - b³. I tried a different approach that I think will work.

I'm assuming you want to show that [tex]\lim_{y \rightarrow -2} f(y) - f(-2) = 0[/tex]

This means you want to show that for any [itex]\epsilon[/itex] > 0 there is a number [itex]\delta[/itex] > 0 such that |f(y) - f(-2)| < [itex]\epsilon[/itex] when |x - (-2)| < [itex]\delta[/itex]
So given such an [itex]\epsilon[/itex], we want
[tex]|(y + 3)^{1/3} - 1| < \epsilon[/tex]
[tex]-\epsilon + 1 < (y + 3)^{1/3} < \epsilon + 1[/tex]
[tex](-\epsilon + 1)^3 < y + 3 < (\epsilon + 1)^3[/tex]
[tex](-\epsilon + 1)^3 - 1 < y + 2 < (\epsilon + 1)^3 -1[/tex]

All that's left is to figure out what you need to use for your [itex]\delta[/itex].