Electric Force problem involving HCl and Br- on coordinate axis

In summary, a hydrogen chloride molecule (HCl) has a partial positive charge on the hydrogen atom and a partial negative charge on the chlorine atom. When placed near a bromide ion, the attractive force from the positively charged hydrogen will be canceled out by the repulsive force of the negatively charged chlorine, resulting in no net force on the bromide ion. This is due to the charges being opposite each other on the x-axis. The y-direction does not come into play in this problem.
  • #1
bbuilder
14
0

Homework Statement



A hydrogen chloride molecule (HCl) has a partial positive charge on the hydrogen atom and a partial negative charge on the chlorine atom. The HCl molecule is placed at

A.
There will be force on the bromide ion in the +x direction.

B.
There will be force on the bromide ion in the -x​ direction.

C.
There will be force on the bromide ion in the +y​
There will be no force on the bromide ion. The attractive force from the positively charged hydrogen will be canceled out by the repulsive force of the negatively charged chlorine.




Homework Equations


p=qd


The Attempt at a Solution


I might be overthinking this problem. I was thinking that the bromide ion be in the positive x-direction to attract it to the partial positive negative ion. I'm confused about how the y-direction might come into play in this problem. I was also thinking that these charges might cancel out because they are directly opposite of each other on the x-axis.
 
Last edited:
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  • #2
Hi bbuilder, welcome to PF.

Make a drawing showing the position of the atoms, and draw arrows showing the magnitude and direction of the forces.


ehild
 
  • #3
The negatively charged chloride is on the -x-axis. The positively charged hydrogen is on the chloride ion has a force on the bromide ion at a positive angle above the horizontal. The positively
 
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  • #4
See the picture. As the HCl molecule is neutral, the positive charge on the hydrogen is equal in magnitude to that of the negative charge on the chlorine. As they are at equal distances from the bromine atom, both the hydrogen and the chlorine atom exert equal forces on the bromine, but the force of the hydrogen is attractive, that of the chlorine is repulsive. See the picture.

What is the direction of the resultant force on the bromine?

Read the problem carefully. All questions refer to the force applied on the bromine atom.

ehild.
 

Attachments

  • HClBr.JPG
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  • #5


Your understanding is correct. The bromide ion will experience a force in the +x direction due to the attractive force from the positively charged hydrogen atom. The force in the +y direction is negligible as the distance between the two particles on the y-axis is likely much larger than their distance on the x-axis. This means that the force in the y-direction is much weaker compared to the force in the x-direction. Additionally, the forces from the positive and negative charges on the HCl molecule will cancel each other out on the x-axis, resulting in no net force in that direction. Therefore, the only significant force acting on the bromide ion will be in the +x direction.
 

Related to Electric Force problem involving HCl and Br- on coordinate axis

1. What is the electric force between HCl and Br-?

The electric force between two particles can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, the electric force between HCl and Br- would depend on the magnitude of their charges and the distance between them on the coordinate axis.

2. How do the charges of HCl and Br- affect the electric force?

The magnitude of the charges of HCl and Br- will directly influence the strength of the electric force between them. The greater the charges, the stronger the force will be. Additionally, the sign of the charges will determine whether the force is attractive or repulsive. Like charges (both positive or both negative) will repel each other, while opposite charges (positive and negative) will attract each other.

3. How does the distance between HCl and Br- impact the electric force?

The distance between HCl and Br- also plays a crucial role in determining the strength of the electric force between them. As the distance increases, the force decreases according to the inverse square law. This means that the force decreases exponentially as the distance increases, making the electric force weaker at greater distances.

4. Can you graph the electric force between HCl and Br- on a coordinate axis?

Yes, the electric force can be graphed on a coordinate axis by plotting the force (y-axis) against the distance between HCl and Br- (x-axis). The resulting graph will show a decreasing trend as the force decreases with increasing distance.

5. How can the electric force between HCl and Br- be used in practical applications?

The electric force between HCl and Br- can be utilized in various practical applications, such as in chemical reactions, electrostatic precipitators, and particle accelerators. It is also crucial in understanding the properties and behavior of different substances and molecules in a variety of scientific fields, such as chemistry, physics, and biology.

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