- #1
NewScientist
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Interesting question - Not homework!
Show that the sum of the infinite series:
[tex] log_2 e - log_4 e + log_{16} e + {(-1^n)} log_{2^{2n}} e ... [/tex]
equals [tex] \frac{1}{ln2\sqrt2} [/tex]
Any ideas?!
Show that the sum of the infinite series:
[tex] log_2 e - log_4 e + log_{16} e + {(-1^n)} log_{2^{2n}} e ... [/tex]
equals [tex] \frac{1}{ln2\sqrt2} [/tex]
Any ideas?!
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