Determining Propagation vector from E(x,y,t)

In summary, the conversation discusses determining the propagation vector from an equation for a plane-polarized wave. The equation includes variables for x, y, and t, and the cosine term involves the propagation vector and time. The conversation also mentions the normalization of the propagation vector and refers to Griffiths Electrodynamics for further understanding.
  • #1
priceless
2
0

Homework Statement



E(x,y,t)=(2i/sqrt(5)) + (j/sqrt(5)) Eo cos( 2pi(1/lamda)[2x/sqrt(5) - y/sqrt(5)]-[ft] )

Homework Equations


I Know k =2pi/lamda for 1D wave
I know K vetor=k dot r
I know K vector shows the direction of propogation, and must be perpendicular to E and B.

The Attempt at a Solution


Got 1/3 points on this part of my exam.
Kvector=2pi (1/lamda) [2/sqrt(5) - 1/sqrt(5)] * (2i/sqrt(5)) + (j/sqrt(5))
I know I have to check for normalizaton, and it is normalized.

Obviously this is wrong. I'm not sure how to define k for a multi dimensional wave, and my textbook does not show any example problems for 3 dimensional waves., or shows solutions for any multidimensional waves that involve K.Is the answer simply the resultant vector of kx and ky?
sqrt( (2/sqrt(5))^2 + (1/sqrt(5))^2)) which just equals sqrt(1)=1.

Edit: Referred back to Griffiths electrodynamics, and think I Figured it out.

K vector = K * r = (2pi/lamda) ( 2x^ / sqrt(5) - 1y^ / sqrt(5))
where x^ and y^ indicate the unit vectors xhat and yhat, not x to a power of ____.
 
Last edited:
Physics news on Phys.org
  • #2
What is your question?
I don't see what the problem statement is.
Also what are the meaning of those i and j, are those things quaternions?
What is the meaning of [ft]?
Four us and for yourself, take a little bit more time to explain your question properly.
 
  • #3
Apologies, it was determine the propagation vector from this equation of a plane-polarized wave.
 
  • #4
Within the cosine, you see something that depends on x,y and something that depends on t.
Propagation has something to do with following time development of points (lines, planes) with constant E through time. ## cos(\vec k \cdot \vec r - \omega t)## I seem to remember.
 
  • #5


Yes, you are correct. The propagation vector, also known as the wave vector, is defined as K = 2π/λ * (n_x * x^ + n_y * y^ + n_z * z^), where n_x, n_y, and n_z are the components of the unit vector in the direction of propagation. In this case, since the wave is only propagating in the x-y plane, the z component can be ignored. The unit vectors x^ and y^ indicate the direction of the x and y axes, respectively. Therefore, the correct answer for the propagation vector in this case would be K = (2π/λ) * (2x^/√5 - y^/√5). It is important to note that the propagation vector is perpendicular to the electric and magnetic fields, as you mentioned.
 

Related to Determining Propagation vector from E(x,y,t)

1. What is a propagation vector?

A propagation vector is a vector that describes the direction and magnitude of the propagation of a wave in space. It is typically denoted as k and is perpendicular to the wavefronts.

2. How do you determine the propagation vector from E(x,y,t)?

The propagation vector can be determined by taking the gradient of the electric field vector E with respect to position x and time t. This can be expressed as k = ∇E(x,y,t) where ∇ is the gradient operator.

3. What is the relationship between propagation vector and wave vector?

The propagation vector and wave vector are related by the wavelength of the wave. The wave vector k is equal to 2π/λ, where λ is the wavelength. Therefore, the propagation vector can also be written as k = 2π/λ.

4. Can the propagation vector change?

Yes, the propagation vector can change depending on the medium through which the wave is propagating. For example, in a medium with varying refractive index, the direction and magnitude of the propagation vector may change.

5. Why is determining the propagation vector important?

Determining the propagation vector is important for understanding the behavior of waves in different mediums and for predicting the direction and speed of wave propagation. It is also a crucial step in the study of wave phenomena, such as diffraction and interference.

Similar threads

  • Advanced Physics Homework Help
Replies
2
Views
947
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
7
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Programming and Computer Science
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
16
Views
1K
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
5
Views
2K
  • Calculus and Beyond Homework Help
Replies
20
Views
556
  • Advanced Physics Homework Help
Replies
4
Views
5K
Back
Top