Deriving the Vector Calculus Equation for Magnetic Force

[hjel0743]

I was reading a paper and came across this equation:

F_magnetic=μ₀(M<dot>∇)H

Is this the correct expansion below? (I'm not too experienced with vectors operating on the gradient operator)

F_magnetic=μ₀[(M_x ∂H/∂x)i + (M_y ∂H/∂y)j + (M_z ∂H/∂z)k]
_____________

My reasoning partially comes from this thread: https://www.physicsforums.com/showthread.php?t=157380

 

[chiro]

Hey hjel0743 and welcome to the forums.

Just for clarification, is M a constant vector and H some kind of function?

 

[hjel0743]

Thanks for the reply chiro! I imagine I'll be here a few more times before my thesis is done... M is a function of H actually, and H is a function of the vector r, representing the radius.

The equation as initially written, describes the force on a particle by a magnetic field. H is the "H-field" and M is the magnetization.

 

[qbert]

[tex]
({\bf M} \cdot \nabla) {\bf H}
= ( ({\bf M} \cdot \nabla H_x) \widehat{i}
+ ({\bf M} \cdot \nabla H_y) \widehat{j}
+ ({\bf M} \cdot \nabla H_z) \widehat{k}).[/tex]

Where, for example,
[tex]
{\bf M} \cdot \nabla H_x = M_x \frac{\partial H_x}{\partial x}
+ M_y \frac{\partial H_x}{\partial y}
+ M_z \frac{\partial H_x}{\partial z}.
[/tex]

 

[chiro]

Assuming your M is a function of x,y,z (in vector form you have M = (Mx,My,Mz) where Mx,My,Mz map R^3 to R for each component) then

del(M) = (d/dx . Mx + d/dy . My + d/dz . Mz)H (I'm assuming everything is Cartesian not a general tensor)
= (dMx/dx + dMy/dy + dMz/dz) H.

Now this will give you the product of two functions but if H is a vector (like M with each component have some transformation from R^3 -> R) then this means you use the scalar form of a*v = (a*v1,a*v2,a*v3) which means if H = (Hx,Hy,Hz) then the whole thing is equal to

(dMx/dx + dMy/dy + dMz/dz) * <Hx,Hy,Hz>

Now M . grad(Hx) = <Mx,My,Mz> . <dHx/dx,dHx/dy,dHx/dz>
= Mx*dHx/dx + My.dHx/dy + Mz.dHx/dz

So they both look the same when they are expanded out, so I imagine you are right in your assertion. (It's been a while since I've done this kind of thing myself).

If I've made a mistake please let me know!