[SOLVED]Complex partial fractions

dwsmith

Well-known member
$$\frac{1}{z^2(1-z)} = \frac{A}{z^2}+\frac{B}{1-z}$$

I can't figure out how to decompose this fraction.

Chris L T521

Well-known member
Staff member
$$\frac{1}{z^2(1-z)} = \frac{A}{z^2}+\frac{B}{1-z}$$

I can't figure out how to decompose this fraction.
You're missing a term. The decomposition should be of the form

$\frac{1}{z^2(1-z)} = \frac{A}{z}+\frac{B}{z^2}+\frac{C}{1-z}$

Is it also to be assumed that $A,B,C\in\mathbb{C}$?