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- Thread starter dwsmith
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- Jan 26, 2012

- 995

You're missing a term. The decomposition should be of the form$$

\frac{1}{z^2(1-z)} = \frac{A}{z^2}+\frac{B}{1-z}

$$

I can't figure out how to decompose this fraction.

\[ \frac{1}{z^2(1-z)} = \frac{A}{z}+\frac{B}{z^2}+\frac{C}{1-z} \]

Is it also to be assumed that $A,B,C\in\mathbb{C}$?