Characteristic polynomial help

In summary, for the given differential equation, there is one real zero with multiplicity 3 and the remaining zeros are complex with multiplicity 2. The solutions for real valued functions with x as the independent variable are a combination of exponential and trigonometric functions, with the complex roots appearing in pairs.
  • #1
roryhand
2
0
y^(7)-y^(6)-2y^(4)+2y^(3)+dy-y=0

Note: There is exactly one real zero of the characteristic polynomial and it
has multiplicity 3 (it is a positive integer!). The other zeros are complex
and they have multiplicity 2.

Sadly I missed this lecture day, and am unsure of where to start. Any differential equation demi-gods out there?
 
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  • #2
For an equation of order n, if a root (say r1) has a multiplicity s (s =< n), where x is the independent variable

[tex] e^{r_{1}x}, xe^{r_{1}x}, x^{2} e^{r_{1}x}, ..., x^{s-1} e^{r_{1}x} [/tex]

For complex roots, let's say [itex] a+bi [/itex] is repeated s times, then the complex conjugate [itex] a-bi [/itex] is also repeated s times, therefore the solutions for real valued functions, where x is the independent variable:

[tex] e^{ax} \cos{bx}, e^{ax} \sin{bx}, xe^{ax} \cos{bx}, xe^{ax} \sin{bx},..., x^{s-1} e^{ax} \cos{bx}, x^{s-1} e^{ax} \sin{bx} [/tex]
 

Related to Characteristic polynomial help

What is a characteristic polynomial?

A characteristic polynomial is a polynomial equation that is associated with a square matrix. It is used to find the eigenvalues of the matrix, which are important values that describe the behavior of the matrix.

How do I calculate the characteristic polynomial of a matrix?

To calculate the characteristic polynomial of a matrix, you need to first find the determinant of the matrix. Then, you will use this determinant to construct the characteristic polynomial by subtracting the determinant from the diagonal elements of the matrix.

Why is the characteristic polynomial important?

The characteristic polynomial is important because it helps us to find the eigenvalues of a matrix. These eigenvalues are useful in many applications, such as finding eigenvectors, solving differential equations, and understanding the behavior of a system.

Can the characteristic polynomial have complex roots?

Yes, the characteristic polynomial can have complex roots. This is because the eigenvalues of a matrix can be complex numbers. In fact, a matrix can have both real and complex eigenvalues, depending on the values in the matrix.

How is the characteristic polynomial related to the characteristic equation?

The characteristic polynomial and the characteristic equation are closely related. The characteristic equation is simply the characteristic polynomial set equal to zero. Solving the characteristic equation will give us the eigenvalues of the matrix.

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