- #1
xkellyy
- 5
- 0
Homework Statement
Suppose f(x,y) = 2x^5 + 4xy + 2y^3
g1(u,v) = u^2 - v^2
g2(u,v) = uv
h(u,v) = f(g1(u,v), g2(u,v))
Use chain rule to calculate:
dh/du (1,-1) and dh/dv (1,-1)
Homework Equations
The Attempt at a Solution
i let h (u,v) = 2(u^2 - v^2)^5 + 4(u^2-v^2)(uv) + 2(u-v)^3
then i tried drawing a chain rule tree diagram:
h --> f --> g1 and g2
g1 --> x and y
g2 --> x and y
so dh/du = (dh/df . df/dx . dx/du) + (dh/df . df/dy . dy/du)
then i got stuck :S
help please?